Answer:
See explanation
Step-by-step explanation:
1. Angles AOM and MOC are supplementry angles. If m∠MOC = 135°, then
m∠AOM = 180° - 135° = 45°
2. OM − angle bisector of ∠AOB, then
m∠AOM = m∠MOB = 45°
3. Now
m∠BOC = m∠MOC - m∠MOB
m∠BOC = 135° - 45° = 90°
4. Since m∠BOC = 90°, BO is perpendicular to AC.
5. Consider isosceles triangle ABC (because AB ≅ BC). BO is the height drawn to the base, so it is an angle B bisector too, thus
∠ABO ≅ ∠CBO
I would have to know the space of the two rectangular prisms to answer this correctly
This can be solved by finding their point of intersection on the graph, which is at point (1,3).
1/2 (6x - 10) + 10 = 5x - 13
(6x/2) - (10/2) + 10 = 5x - 13
3x - 5 + 10 = 5x - 13
3x - 5x = -13 + 5 - 10
-2x = -18
x = -18 / -2
x = 9
D.) x = 9
Answer:
A ................................
