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djyliett [7]
3 years ago
9

Charles is going to purchase a new car that has a list price of $21,450. He is planning on trading in his good-condition 2004 Do

dge Neon and financing the rest of the cost over three years, paying monthly. His finance plan has an interest rate of 12.28%, compounded monthly. Charles will also be responsible for 6.88% sales tax, a $1,089 vehicle registration fee, and a $124 documentation fee. If the dealer gives Charles 80% of the listed trade-in price on his car, once the financing is paid off, what percent of the total amount paid will the interest be? (Consider the trade-in to be a reduction in the amount paid.) Dodge Cars in Good Condition Model/Year 2004 2005 2006 2007 2008 Viper $7,068 $7,225 $7,626 $7,901 $8,116 Neon $6,591 $6,777 $6,822 $7,191 $7,440 Intrepid $8,285 $8,579 $8,699 $9,030 $9,121 Dakota $7,578 $7,763 $7,945 $8,313 $8,581 a. 17.64% b. 15.67% c. 16.70% d. 12.86%
Mathematics
1 answer:
devlian [24]3 years ago
7 0
The answer is c. 16.70% This is based on the posts I've read online regarding this problem. No solution was given.

These are the amounts you have to consider:
List price of new car - 21,450
Sales tax rate: 6.88% - 21,450 x 6.88% = 1,475.76
vehicle registration fee - 1,089
documentation fee - 124
loan term - 3 years, paid monthly. so, 36 months
interest rate - 12.28% compounded monthly. 
2004 Dodge Neon value - 6,591
trade in value - 6,591 x 80% =  5,272.80

No mention of down payment so the possible amount to be financed is: 24,138.76
The value of the traded car is only considered after the financing has been paid off. 

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A school wishes to enclose its rectangular playground using 480 meters of fencing.
Harlamova29_29 [7]

Answer:

Part a) A(x)=(-x^2+240x)\ m^2

Part b) The side length x that give the maximum area is 120 meters

Part c) The maximum area is 14,400 square meters

Step-by-step explanation:

The picture of the question in the attached figure

Part a) Find a function that gives the area A(x) of the playground (in square meters) in terms of x

we know that

The perimeter of the rectangular playground is given by

P=2(L+W)

we have

P=480\ m\\L=x\ m

substitute

480=2(x+W)

solve for W

240=x+W\\W=(240-x)\ m

<u><em>Find the area of the rectangular playground</em></u>

The area is given by

A=LW

we have

L=x\ m\\W=(240-x)\ m

substitute

A=x(240-x)\\A=-x^2+240x

Convert to function notation

A(x)=(-x^2+240x)\ m^2

Part b) What side length x gives the maximum area that the playground can have?

we have

A(x)=-x^2+240x

This function represent a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the length that give the maximum area that the playground can have

Convert the quadratic equation into vertex form

A(x)=-x^2+240x

Factor -1

A(x)=-(x^2-240x)

Complete the square

A(x)=-(x^2-240x+120^2)+120^2

A(x)=-(x^2-240x+14,400)+14,400

A(x)=-(x-120)^2+14,400

The vertex is the point (120,14,400)

therefore

The side length x that give the maximum area is 120 meters

Part c) What is the maximum area that the playground can have?

we know that

The y-coordinate of the vertex represent the maximum area

The vertex is the point (120,14,400) -----> see part b)

therefore

The maximum area is 14,400 square meters

Verify

x=120\ m

W=(240-120)=120\ m

The playground is a square

A=120^2=14,400\ m^2

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Answer:x=750

Step-by-step explanation:

2/3(x)+ 1/4(x) + 375

(9/12)x - (3/12)x = 375

(6/12)x + 375

8 0
3 years ago
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A Sum of $14 is made of 92 coins consisting of dimes and quarters. How Many are there of each kind of coin
steposvetlana [31]
So first I would say, what if all of them were dimes, how far away would it be from $14?

So 92 coins * 10 cents = $9.20

So it's 4.80 dollars away from 14 dollars.

So if we were to switch one to a quarter, it would increase by 0.15 cents.

So we want to see how many increases we need to reach 4.80 dollars more.

4.80/0.15 = 32

So there are 32 quarters and 60 dimes.
7 0
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Oksana_A [137]

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san4es73 [151]

Answer:

B. AC = 22, BC = 22, AB = 44

C. AC = 30, BC = 30, AB = 60

Step-by-step explanation:

B.

radius \: \overline {OR} \perp chord \: \overline {AB} at C. (given)

\therefore AC = BC (perpendicular dropped from the center of the circle to the chord bisects the chord)

\therefore 2x - 6 = x + 8

\therefore 2x - x= 6 + 8

\therefore x= 14

AC = 2x-6=2(14)-6=28-6= 22

BC= x + 8=14 + 8= 22

AB = AC + BC = 22 + 22 = 44

C.

radius \: \overline {OR} \perp chord \: \overline {AB} at C. (given)

\therefore BC = AC (perpendicular dropped from the center of the circle to the chord bisects the chord)

\therefore 7x-5=4x+10

\therefore 7x - 4x= 5 + 10

\therefore 3x= 15

\therefore x= \frac{15}{3}

\therefore x= 5

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BC= 7x - 5=7(5)-5=35-5= 30

AB = AC + BC = 30 + 30 = 60

7 0
3 years ago
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