The coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent
- The given figures are quadrilaterals, in order to determine whether they are similar, we need to check if they are reflections of each other.
- For the Quadrilateral ABCD, the coordinate of A is at A(-1, 1) and for the Quadrilateral DEFG, the coordinate of E is at E(1, 1).
- Note that if an object is reflected over the y-axis the transformation is (x, y)->(-x, y)
- We need to check whether if we reflect the coordinate A over the y-axis we will get coordinate E
Since the coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent
Learn more on reflections here:brainly.com/question/1908648
If this is just addition, then it would be 18, other than that, I dont know. Or I am dumb.
Answer:
5 00000
Step-by-step explanation:
bc it just is lolllllll
Answer:
k = ln (6/5)
Step-by-step explanation:
for
f(x)=A*exp(kx)+B
since f(0)=1, f(1)=2
f(0)= A*exp(k*0)+B = A+B = 1
f(1) = A*exp(k*1)+B = A*e^k + B = 2
assuming k>0 , the horizontal asymptote H of f(x) is
H= limit f(x) , when x→ (-∞)
when x→ (-∞) , limit f(x) = limit (A*exp(kx)+B) = A* limit [exp(kx)]+B* limit = A*0 + B = B
since
H= B = (-4)
then
A+B = 1 → A=1-B = 1 -(-4) = 5
then
A*e^k + B = 2
5*e^k + (-4) = 2
k = ln (6/5) ,
then our assumption is right and k = ln (6/5)
