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erma4kov [3.2K]
3 years ago
9

7 1/2 - 5 2/3 explained

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0
Exact form: 11/6

decimal form: 1.83333333

mixed number: 1 5/6
worty [1.4K]3 years ago
3 0
So multiply 1 by 2 and add 1
and same with 5 times 3 plus 2
\frac{15}{2} - \frac{17}{3}
Which would be \frac{11}{6}
So, your answer would be as a mix number
1 \frac{5}{6}
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Determine if the two figures are congruent and explain your answer using transformations.
Maslowich

The coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent

  • The given figures are quadrilaterals, in order to determine whether they are similar, we need to check if they are reflections of each other.

  • For the Quadrilateral ABCD, the coordinate of A is at A(-1, 1)  and for the Quadrilateral DEFG, the coordinate of E is at E(1, 1).

  • Note that if an object is reflected over the y-axis the transformation is (x, y)->(-x, y)

  • We need to check whether if we reflect the coordinate A over the y-axis we will get coordinate E

Since the coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent

Learn more on reflections here:brainly.com/question/1908648

7 0
2 years ago
This model stands for 128.
Airida [17]
If this is just addition, then it would be 18, other than that, I dont know. Or I am dumb.
6 0
3 years ago
Read 2 more answers
Please help answer correctly !!!!!!!!! Will mark Brianliest !!!!!!!!! URGENT
krek1111 [17]

Answer:

5 00000

Step-by-step explanation:

bc it just is lolllllll

7 0
3 years ago
A function f is described by f(x)=A*exp(kx)+B, where A, B and k are constants. Given f(0)=1, f(1)=2, and that the horizontal asy
s2008m [1.1K]

Answer:

k = ln (6/5)

Step-by-step explanation:

for

f(x)=A*exp(kx)+B

since f(0)=1, f(1)=2

f(0)= A*exp(k*0)+B = A+B = 1

f(1) = A*exp(k*1)+B =  A*e^k + B = 2

assuming k>0 , the horizontal asymptote H of f(x) is

H= limit f(x) , when x→ (-∞)

when x→ (-∞) , limit f(x) =  limit (A*exp(kx)+B) = A* limit [exp(kx)]+B* limit = A*0 + B = B

since

H= B = (-4)

then

A+B = 1 → A=1-B = 1 -(-4) = 5

then

A*e^k + B = 2

5*e^k + (-4) = 2

k = ln (6/5)    ,

then our assumption is right and k = ln (6/5)  

8 0
3 years ago
Find the Perimeter <br> and Area <br> of the following:
Lynna [10]
Peramter 7 and area 49
5 0
3 years ago
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