MN = 6 in
add the parts of the ratio, 1 + 2 + 3 = 6
divide AB by 6 to find 1 part of the ratio
= 3 ← 1 part
AM = 3 in ← 1 part
MN = 2 × 3 = 6 in ← 2 parts
NB = 3 × 3 = 9 in ← 3 parts
and 3 + 6 + 9 = 18 in = AB
Its Letter A see photo for solution
Answer:
1) 102/21
2) 21/51
3) 21/24
Step-by-step explanation:
Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
