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3 years ago

14

Mrs. Summer's third grade class is putting on a play. If she has 13 1/8 yards of fabric, and each student needs 7/8 of a yard fo

r a costume, how many students can make costumes?

2 answers:

Juliette [100K]3 years ago

7 0

15. 7/8 times 15 equals 13.125 (or 13 1/8)

AfilCa [17]3 years ago

6 0

I'm not quite sure, but just subtract 7/8 from 13 and 1/8 for each student until you can't anymore and there's your answer! Hope this helps. (:

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Please help asap

Nostrana [21]

I Think The answer is d I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you

6 0

2 years ago

Simplify 3/5+(-1/4) 7/10

Vadim26 [7]

Answer:

17/40

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

3 years ago

HELP PLEASE DUE IN 3 MINUTES

Morgarella [4.7K]

Answer: it is d becaues that is the mode

4 0

3 years ago

Vince bought 6 boxes of worms to use as bait while fishing with his friends. If each person uses exactly 3/8 of a box of worms,

tia_tia [17]

We are given the following information:

<em />

<em>each person uses 3/8 a box</em>

<em>there are 6 boxes</em>

Because each box is $\frac{8}{8}$ , and there are 6 boxes, we know that 1 person is $\frac{3}{8*6}$ , or $\frac{3}{48}$ .

In order to find how many people can use the 6 boxes, we can divide it by 3 (for each use):

48 / 3 = 16

Therefore, 16 people can share the worms.

<em>Hope this helps! :)</em>

4 0

3 years ago