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Free_Kalibri [48]
3 years ago
15

Which of the following is an example of a complex machine?

Biology
2 answers:
yarga [219]3 years ago
7 0

3- Scissors are an example of a complex machine.

Alchen [17]3 years ago
3 0

Answer:

The correct answer is "Pulley"

Explanation:

I just took the test

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- How would you classify the relationship between coral and the small crabs?
skelet666 [1.2K]

Answer:

Explanation:

How would you classify the relationship between coral and the small crabs? Their relationship is mutualistic, as the crabs provide protection for the coral reef and the reef provides the crabs a home.

7 0
2 years ago
Please use the following case for questions.
barxatty [35]

Answer:

Explanation:

a) the cardiovascular condition is sabacute endocarditis

b) It is caused by a type of streptococcus called streptococcus viridians and transmitted through the opening of the wound

c) rheumatic fever can lead to damage to the heart and this damage allows bacteria to attach itself to the heart. Streptococcus viridians are often caused by bacteria hence there growth can be favorite by rheumatic fever.

d) the nails is used to check the blood stream, and should be check for capillary heamorrhage

e) He would order for BAP- Bacteria Agar plate that is used mostly to classic streptococcal bacteria.

5 0
3 years ago
Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
3 years ago
What is the result of a substitution mutation?
expeople1 [14]

Answer:

The new amino acid may be the same as the original amino acid or it may be different.

3 0
3 years ago
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Prokaryotes, like most living organisms, need movement to locate food and to survive.
zmey [24]

Answer:

Explanation:

Prokaryotes, like most living organisms, need movement to locate food and to survive. If a prokaryote needed to move to a new food source, which structure would it use for locomotion?

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