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brilliants [131]
3 years ago
12

6.5 Code Practice: Question 1 please help with code!!! Thank you

Computers and Technology
1 answer:
viva [34]3 years ago
7 0

Answer: Eat my boy toy

Explanation:

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Virus is a type of malware which is used in this case.

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What was the worlds first coding language
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An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .
Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

{

// Check if arrays has one or no elements

if (count == 1 || count == 0) {

return 1;

}

else

{

// Check first two elements

if(arr[0] >= arr[1])

{

return 0; // Not sorted

}

else

{ // Check other elements

int check = 0;

for(int I = 1; I<count; I++){

if (arr[I-1] > arr[I]) { // Equal number are allowed

check++; // Not sorted

}

}

}

if(check==0)

return isSorted(arr, count - 1); //Sorted

else

return 0; // Not sorted

}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

cout << "Array is sorted";

else

cout << "Array is not sorted";

}

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4 years ago
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Bezzdna [24]
Speakers is your answer
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Write a recursive function that returns 1 if an array of size n is in sorted order and 0 otherwise. Note: If array a stores 3, 6
Tanzania [10]

Answer:

Here the code is given as follows,

Explanation:

Code:-

#include <stdio.h>  

int isSorted(int *array, int n) {

   if (n <= 1) {

       return 1;

   } else {

       return isSorted(array, n-1) && array[n-2] <= array[n-1];

   }

}  

int main() {

   int arr1[] = {3, 6, 7, 7, 12}, size1 = 5;

   int arr2[] = {3, 4, 9, 8}, size2 = 4;  

   printf("%d\n", isSorted(arr1, size1));

   printf("%d\n", isSorted(arr2, size2));

   return 0;

}

Output:-

4 0
3 years ago
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