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MAXImum [283]
3 years ago
13

A water sprinkler has a range of 5 meters as shown. The jet of water from the sprinkler sweeps out at an angle of 85° as the noz

zle turns. What is the area watered by the sprinkler? Use the value π = 3.14, and round your answer to one decimal place.
Mathematics
2 answers:
Mashutka [201]3 years ago
8 0
 3.14*5^2=78.5
78.5*85/360=18.5
vivado [14]3 years ago
3 0

Answer:

Step-by-step explanation:

Alright, lets get started.

The given angle is 85°.

Lets convert this angle into radian first.

For this we have to multiply this with \frac{\pi }{180}

So the angle in radian is = 85*\frac{\pi}{180}=1.4835

The formula of area is = \frac{1}{2}angle*r^2

Area = \frac{1}{2}*1.4835*5^2

Area = 18.5 square meter   :   Answer

Hope it will help :)

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Thepotemich [5.8K]

Answer:

ok so first you have to know what a reflectiin along 180 is

) A point P(x,y)P(x,y) is rotated 180180 degrees about the origin, then reflected over the y-axis. What is the resulting image of PP?

My conjecture: (−x,y)(−x,y) but I don't quite agree with it graphically. I'm having trouble with what exactly a 180 degree rotation about the origin simply is.

2) A point P(x,y)P(x,y) is reflected over the y-axis and then rotated 180 degrees about the origin. What is the resulting image?

Is this the same thing as 1?

3) A point A(x,y)A(x,y) is reflected over the line y=xy=x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (−y,x)(−y,x)

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Step-by-step explanation:

)If P(x1,y1)P(x1,y1) is rotated angle ϕϕ about O(a,b)O(a,b) to P′(x′,y′)P′(x′,y′)

we have |OP|=|OP′||OP|=|OP′| and |arctanmOP−arctanmOP'|=ϕ|arctan⁡mOP−arctan⁡mOP'|=ϕ

By atan(z)(z) I imply atan2

(2)If P(x1,y1)P(x1,y1) is reflected over L:ax+by+c=0L:ax+by+c=0 and the resulting image of PP is Q(x2,y2)    (1)Q(x2,y2)    (1)

We have R

so i hope thiz helprs you

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Step-by-step explanation:

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