do you some help ?, I can try my best to help
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
To learn more about the solution visit:
brainly.com/question/1397278
16 gal... 480 mi
1 gal... 480/16 = 30 mi
9 gal.. 30*9 = 270 mi
Answer:
2.2%
Step-by-step explanation:
Given the following :
Population in year 2000 (A) = 4.2 million
Expected population every 32 years = 2 *A
The growth rate per year =?
The population figure after 32 years = (2 * 4.2 million) = 8.4 million
Using the exponential growth formula :
P(t) = A × (1 + r)^t
(1 + r) = g = Total growth percent
A = Initial population
t = time
P(t) = 8.4 million
8,400,000 = 4,200,000 × g^32
g^32 = (8400000/4200000)
g^32 = 2
Taking the root of 32 on both sides
g = 1.02189714865
g = (1 + r)
1.02189714865 = 1 + r
r = 1.02189714865 - 1
r = 0.02189714865
.rate = 0.02189714865 * 100
= 2.18971486541%
= 2.2% ( nearest tenth)
Answer:
7
Step-by-step explanation:
