Step by step solution :<span>Step 1 :</span><span>Equation at the end of step 1 :</span><span><span> (((3•(x2))•(y4))3)
4•——————————————————
((2x3•(y5))4)
</span><span> Step 2 :</span></span><span>Equation at the end of step 2 :</span><span><span> ((3x2 • (y4))3)
4 • ———————————————
24x12y20
</span><span> Step 3 :</span><span> 33x6y12
Simplify ————————
24x12y20
</span></span>Dividing exponential expressions :
<span> 3.1 </span> <span> x6</span> divided by <span>x12 = x(6 - 12) = x(-6) = 1/<span>x6</span></span>
Dividing exponential expressions :
<span> 3.2 </span> <span> y12</span> divided by <span>y20 = y(12 - 20) = y(-8) = 1/<span>y8</span></span>
<span>Equation at the end of step 3 :</span><span> 27
4 • ——————
16x6y8
</span><span>Step 4 :</span>Final result :<span> 27
—————
4x6y<span>8</span></span>
Answer:
400 x however long those ribbons are
Step-by-step explanation:
1 meter is 100 centimeters, and there are four rolls. so 4x100 equals 400, and you multiply that by the length that you didn't provide.
Answer:
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
Step-by-step explanation:
Volume of the Cylinder=400 cm³
Volume of a Cylinder=πr²h
Therefore: πr²h=400
Total Surface Area of a Cylinder=2πr²+2πrh
Cost of the materials for the Top and Bottom=0.06 cents per square centimeter
Cost of the materials for the sides=0.03 cents per square centimeter
Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)
C=0.12πr²+0.06πrh
Recall:
Therefore:
The minimum cost occurs when the derivative of the Cost =0.
r=3.17 cm
Recall that:
h=12.67cm
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
