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Aleks [24]
3 years ago
13

Mitch lost

Mathematics
1 answer:
MrMuchimi3 years ago
4 0
<span>The answer is A<span>)<span>10/3 over <span>5/7.

</span></span></span></span>
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Simplify: 4(3x^2y^4)^3 / 2x^3y^5)^4
Semenov [28]
Step by step solution :<span>Step  1  :</span><span>Equation at the end of step  1  :</span><span><span> (((3•(x2))•(y4))3) 4•—————————————————— ((2x3•(y5))4) </span><span> Step  2  :</span></span><span>Equation at the end of step  2  :</span><span><span> ((3x2 • (y4))3) 4 • ——————————————— 24x12y20 </span><span> Step  3  :</span><span> 33x6y12 Simplify ———————— 24x12y20 </span></span>Dividing exponential expressions :

<span> 3.1 </span>  <span> x6</span> divided by <span>x12 = x(6 - 12) = x(-6) = 1/<span>x6</span></span>

Dividing exponential expressions :

<span> 3.2 </span>  <span> y12</span> divided by <span>y20 = y(12 - 20) = y(-8) = 1/<span>y8</span></span>

<span>Equation at the end of step  3  :</span><span> 27 4 • —————— 16x6y8 </span><span>Step  4  :</span>Final result :<span> 27 ————— 4x6y<span>8</span></span>
6 0
3 years ago
Read 2 more answers
3. Bobbi bought 4 rolls of
sveta [45]

Answer:

400 x however long those ribbons are

Step-by-step explanation:

1 meter is 100 centimeters, and there are four rolls. so 4x100 equals 400, and you multiply that by the length that you didn't provide.

3 0
2 years ago
F (x) = 3x + 7 <br> F (-4) = <br> F (2) =
V125BC [204]

Answer:

f(-4)=3(-4)+7=0

f(2)=3(2)+7=13

3 0
3 years ago
Read 2 more answers
A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0
3 years ago
I had $20.00 my mom gave me $10.00 my dad gave me 30.00 my aunt and uncle gave me $100.00 I had another $1.00 how much did I hav
sweet-ann [11.9K]

Answer:

$161

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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