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chubhunter [2.5K]
4 years ago
15

exactly 512 small cubes perfectly fill a lidless cubical box. All of the small cubes were removed except those touching the bott

om of the box and those touching the sides of the box. How many of the small cubes were removed
Mathematics
1 answer:
Vladimir [108]4 years ago
6 0

Answer: 216

Step-by-step explanation:

Since, a cube is a 3D structure,

We can understand this problem by assuming the figure in the coordinate axis.

In which, The cubes in the box along x-axis = 10

Along y-axis = 10

Along z-axis = 10

Total cubes along each x, y, z directions those are not appearing on surface are (10-2), (10-2), (10-2) = 8, 8, 8  

Therefore total cubes which are not shown on the surface of the cube= 6\times 6\times 6 = 216.

Since, the box that are not in the surface are removed.

Thus, the total boxes that are removed = 216

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last year 240 new houses were built and so far this year 7/8 of them have been sold. How many houses have been sold this year?​
musickatia [10]

Answer:

210 houses sold

Step-by-step explanation:

7/8 of 240

240 divided by 8=30

30 x 7 = 210

hope this helps

Brainiest plz?

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5 0
3 years ago
. 10(7x - 2) + 3(-7X - 8)
n200080 [17]

Answer:

49x-44 is it.

Step-by-step explanation:

8 0
3 years ago
A dog owner is told by the veterinarian that his dog, Max, is overweight and needs to lose 4 to 5 pounds in order to live a heal
hodyreva [135]
This is a linear function, of the kind y = mx + b

where x is the number of visit,  b is the weight when x = 0, and m is the predicted change of weight for every visit.

m = - 4 ounces / visit, which must be converted to pounds (the negative sign indicates that the change is a decrease)

1 lb = 16 ounces = 4 ounces = 0.25 lb

Then m = - 0.25 lb / visit.

Now, for x = 1, y = 126 => 126 = - 0.25(1) + b => b = 126 + 0.25 = 126.25

Then the function is y = 126.25 - 0.25x

Now round to the nearest tenth:

y = 126.3 - 0.3x

Answer: y = 126.3 - 0.3x

 

6 0
3 years ago
The graph of f(x)=x2 is shown. Use the parabola tool to graph the function g(x)=(12x)2. To graph a parabola, first plot the vert
Talja [164]

Answer:

Pease check my assumptions.

Step-by-step explanation:

I will assume that f(x)=x2 is actually f(x) = x^2.

Same for g(x)=(12x)^2  [Is it g(x)=12x^2  ???]

See the attached image.

Note that (12x)^2 results in a narrower, steeper graph.   That's because (12x)^2 can be rewritten as 144x^2, so every value is multiplied by 144, compared to just x^2.

7 0
2 years ago
National data in the 1960's showed that about 44% of the adult population had never smoked cigarettes. In 1995 a national health
Marta_Voda [28]

Answer:

a) 0.52 - 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.487

0.52 + 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.553

The 95% confidence interval would be given by (0.487;0.553)

b) After see the confidence interval we see that the lower limits 0.487>0.44 with 0.44 or 44% the estimated  proportion for 1960, we can conclude that we have a significant increase in the adult proportion had never smoked cigarettes.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.52 - 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.487

0.52 + 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.553

The 95% confidence interval would be given by (0.487;0.553)

Part b

After see the confidence interval we see that the lower limits 0.487>0.44 with 0.44 or 44% the estimated  proportion for 1960, we can conclude that we have a significant increase in the adult proportion had never smoked cigarettes at 5% of significance.

4 0
4 years ago
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