If these are terms of a geometric sequence, they have a common ratio. That is, ...
... (k -1)/(2(1 -k)) = (k +8)/(k -1)
... (k -1)² = 2(1 -k)(k +8) . . . . . multiply by the product of the denominators.
... k² -2k +1 = -2k² -14k +16 . . . eliminate parentheses
... 3k² +12k -15 = 0 . . . . . . . . put in standard form (subtract the right side)
... 3(k +5)(k -1) = 0 . . . . . . . . . factor
Possible values of k are ... -5, +1. The solution k=1 is extraneous, as it makes the first two terms 0 and the third term 8. (It doesn't work.)
The value of k is -5.
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The three terms are 12, -6, 3. The common ratio is -1/2.
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Answer:
x ≥ 15/2 im pretty sure
Step-by-step explanation:
reduce the fraction: -7 ≤ x + 1/2. move the terms: -x ≤ 1/2 + 7 calculate the sum: -x ≤ 1/2 + 7 = -x ≤ 15/2 and change the signs: x ≥- 15/2.
Answer:
B
Step-by-step explanation:
Because I got it right
Use the information to form a ratio... 6:8 or 6/8. Now set it equal to a ratio per 100...
6/8 = x/100
Cross multiply
8x = 600
x = 600/8
x = 75
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