Answer to the miscellaneous equation, is x=0
Miscellaneous equation are the equations which are not polynomial.
The question can be solved by:
Factorising:Splitting the terms to find the required solution
Completing the squares, etc
2ˣ -3ˣ=√(6ˣ-9ˣ)
-> (2ˣ -3ˣ)²=(3ˣ.2ˣ - 3²ˣ)
Squaring both sides,
-> 2²ˣ+3²ˣ- 2.3ˣ.2ˣ=(3ˣ.2ˣ - 3²ˣ)
-> 2²ˣ+2.3²ˣ-2.3ˣ.2ˣ-3ˣ.2ˣ=0
Factorising the terms,
-> 2ˣ(2ˣ-3ˣ) -2.3ˣ(2ˣ-3ˣ)=0
-> (2ˣ-3ˣ)(2ˣ-2.3ˣ)=0
Equating the braces to zero,
x=0 is the only solution.
Therefore, x =0 is the only solution
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Answer:
B) 0.0000000000003
Step-by-step explanation:
Hope this helps.
Answer:
<h2>Your answer would be <em><u>0.34</u></em></h2>
Step-by-step explanation:
first we add them altogether:
0.25+0.17+0.21+0.03 = 0.66
than we subtact the 0.66 from the whole (1) =
<u>1-0.66= 0.34</u>
Answer:
69.75
Step-by-step explanation:
Answer:
a) N = 240 ways
b) N = 303,600 ways
c) N = 10 ways
Step-by-step explanation:
a) Given
General course consist of one course from each of 4 groups.
Social Science = 5 options
Humanities = 4 options
Natural sciences = 4 options
Foreign language = 3 options.
Therefore the total number of possible ways of selecting one each from each of the 4 groups is:
N = 5×4×4×3 = 240 ways
b) if four people are chosen from 25 member for four different positions, that makes it a permutation problem because order of selection is important.
N = nPr = n!/(n-r)!
n = 25 and r = 4
N = 25P4 = 25!/(25-4)! = 25!/21!
N = 303,600 ways
c) The number of ways by which 5 tosses of coin can yield 2 heads and 3 tails.
N = 5!/(5-5)!(2!)(3!)
N = 5×4/2
N = 10 ways
