Answer:
RS = 2
Step-by-step explanation:
Points R, S, and T are collinear, and S is between R and T, in addition, RS = 2x-4, ST = 3x+2, and RT = 13. Find the value of RS
Hence:
RS + ST = RT
2x - 4 + 3x + 2 = 13
2x + 3x - 4 + 2 = 13
5x - 2 = 13
5x = 13 + 2
5x = 15
x = 15/5
x = 3
To find the value of RS
RS = 2x-4
RS = 2 × 3 - 4
RS = 6 - 4
RS = 2
Answer:
System A the answer is: One solution
System B the answer is: Many infinite solution
System C the answer is: No solution
Step-by-step explanation:
Hope this helps you :)
Remember that the formula for the circumference,
, of a circle is:

In this case, we are not given the diameter. However, remember that the diameter is equivalent to two times the radius of a circle. Thus,
,
and we can say the circumference of our circle is:

The circumference of our circle is 50.24 units.
<em>Also, a little side note not relating to the question:</em>
<em>Remember that
is spelled as "pi" not "pie." Pie is a dessert, while pi is a mathematical constant.</em>
Answer:
x=-4 x=-2
Step-by-step explanation:
x² + 6x + 8 = 0
x² +2x+4x + 8 = 0
x(x+2)+4(x+2)=0
(x+4)(x+2)
x=-4 x=-2
Answer:
The probability that the restaurant can accommodate all the customers who do show up is 0.3564.
Step-by-step explanation:
The information provided are:
- At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
- If the probability of a party not showing up is 0.04.
- Assuming independence.
Let <em>X</em> denote the number of parties that showed up.
The random variable X follows a Binomial distribution with parameters <em>n</em> = 53 and <em>p</em> = 0.96.
As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.
Compute the probability that the restaurant can accommodate all the customers who do show up as follows:
![P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564](https://tex.z-dn.net/?f=P%28X%5Cleq%2050%29%3D1-P%28X%3E50%29%5C%5C%3D1-P%28X%3D51%29-P%28X%3D52%29-P%28X%3D53%29%5C%5C%3D1-%5B%7B53%5Cchoose%2051%7D%280.96%29%5E%7B51%7D%280.04%29%5E%7B53-51%7D%5D-%5B%7B53%5Cchoose%2052%7D%280.96%29%5E%7B52%7D%280.04%29%5E%7B53-52%7D%5D%5C%5C-%5B%7B53%5Cchoose%2053%7D%280.96%29%5E%7B53%7D%280.04%29%5E%7B53-53%7D%5D%5C%5C%3D1-0.27492-0.25377-0.11491%5C%5C%3D0.3564)
Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.