Divide (6x3y2 + 12x2y - 8xy) by (2xy)

Mathematics

1 answer:

rosijanka [135]2 years ago

5 0

Answer:

Step-by-step explanation:

6x³y² = 2 * 3 * x³ * y²

12x²y = 2 *3 * 2 * x² * y

8xy = 2 * 2 * 2 *x * y

GCF = 2xy

6x³y² + 12x²y - 8xy = (2xy * 3x²y) + (2xy * 6x) - (2xy * 4)

= 2xy *(3x²y + 6x - 4)

$\dfrac{6x^{3}y^{2}+12x^{2}y-8xy}{2xy}=\dfrac{2xy*(3x^{2}y+6x-4)}{2xy}\\\\\\= 3x^{2}y + 6x - 4$

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