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mote1985 [20]
3 years ago
7

Solve for r. 19 − 17r = -16r

Mathematics
1 answer:
ELEN [110]3 years ago
8 0

Answer:

$19=r$

Step-by-step explanation:

$19-17r=-16r$

Add 17r to both sides:

$19-17r+17r=-16r+17r$

$19=-16r+17r$

$19=r$

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12'<br>Given that tan x =<br>sin x + cos x?<br>î, what is the value of<br>(WAEC]​
Andre45 [30]

Answer:

\tan(x) =  \sin(x)  +  \cos(x)

Sorry but your question is not too explanatory but I sure hope this helps

3 0
3 years ago
3 is what percentage of 5
cupoosta [38]

Answer:

60%

Step-by-step explanation:

is means equals and of means multiply

3 = P * 5

divide each side by

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Change to a percentage by multiplying by 100

60%

6 0
3 years ago
Read 2 more answers
16 The cost for parking at a city airport is shown in the table.
Alexxx [7]

Answer:

He paid $9 twelve times

12× 2= 24 days

Step-by-step explanation:

1st day = $16.60

3rd day=$ 9 (i.e for every 2days afterwards)

5th day=$ 9

Yuri pays : 124.60

124.60-16.60

= $108.00

After paying the first day he paid 108.00

108.00÷ 9 = 12

He paid $9 twelve times

12× 2= 24 days

3 0
2 years ago
I need to know what is expected
bearhunter [10]

Answer:

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Is it cool?

8 0
3 years ago
In your top dresser drawer are 6 blue socks and 10 grey socks, unpaired and mixed up. One dark morning you pull two socks from t
pishuonlain [190]

Answer:

D) 0.500

Step-by-step explanation:

Blue Socks = 6

Grey socks = 10

Probabilities to find :

Since there are a total of 16 socks, the probability of both socks being blue is  

Probability(blue) = (\frac{6}{16} ) \frac{5}{15} =\frac{30}{240} =\frac{1}{8}

The probability of both being grey is  

Probability(grey)  =(\frac{10}{16} ) \frac{9}{15} =\frac{90}{240} =\frac{3}{8}

(Note: After 1 sock is picked , next sock drawn would have a different probability as 1 sock is already picked so it would be 1 minus the total socks available of that color)

The probability two socks match:

Probability(blue) + Probability(grey) = \frac{1}{8} + \frac{3}{8}  = \frac{4}{8}  =\frac{1}{2} = 0.500

5 0
3 years ago
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