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Alborosie
3 years ago
10

What is the x-intercept of the line with this equation 1/3x+y=−15

Mathematics
1 answer:
serg [7]3 years ago
6 0
The x-intercept is -45.

Substitute 0 for y to find x-intercept

Substitute 0 for x to find y-intercept
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Find the surface area of the prism.
joja [24]
Multiply it && get your answer the fraction is 1.20
4 0
3 years ago
Angelica's salary this year is 14% higher than it was four years ago. If she earns $46,170.00 this year, what did she earn four
Alona [7]

Answer:

D. $39,706.20

Step-by-step explanation:

In this problem, you are subtracting 14%. A way you could do this is buy finding 14% of $46,170.00, then subtracting that from itself. Or instead, you could find 86%. This works because its like your subtracting 14% from the whole 100%. so 100 - 14 = 86.

Method 1:

$46,170.00 x 0.14 = 6463.8

$46,170.00 - 6463.8 = 39706.2

Method 2:

100 - 14 = 86

$46,170.00 x 0.86 = 39706.2

either way the answer is still correct. i hope this make sense and that it helps you!

5 0
2 years ago
PLSSSS HELLPPPP MEEEEE I WILLL GIVEEE BRAINLIESSSTTT!!!!
Kazeer [188]

Answer:

4 quizzes are taken per week

3 0
3 years ago
Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
2 years ago
What time is 6 3/4 hours before 3:37a.m
Mrac [35]
10:12 pm 

6 hours before is 9pm
3/4=45/60
add 45+37=72-60=12=1+9=10:12
4 0
3 years ago
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