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Nikitich [7]
3 years ago
13

As a promotion, the first 50 customers who entered a certain store at a mall were asked to choose from one of two discounts. The

first discount choice was 20% off all purchases made that day. The second discount choice was 10% off all purchases for the week. Of those who received the discounts, 28 chose the first discount and 22 chose the second discount. One customer will be selected at random from those who received a discount. Let F represent the event that the selected person chose the first discount, and let S represent the event that the selected person chose the second discount.
Requried:
Are F and S mutually exclusive events?
Mathematics
1 answer:
julsineya [31]3 years ago
3 0

Answer: rerere

Step-by-step explanation: rerer

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A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored
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Answer:

Mutually exclusive,

P(\text{Lemon-lime or orange})=\frac{2}{3}

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the  probability.

A cooler contains twelve bottles of sports  drink: four lemon-lime flavored, four  orange flavored, and four fruit-punch  flavored. You randomly grab a bottle. It  is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}

P(\text{Lemon-lime})=\frac{4}{12}

P(\text{Lemon-lime})=\frac{1}{3}

Let us find probability of finding one orange drink.

P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}

P(\text{Orange})=\frac{4}{12}

P(\text{Orange})=\frac{1}{3}

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})

P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}

P(\text{Lemon-lime or orange})=\frac{1+1}{3}

P(\text{Lemon-lime or orange})=\frac{2}{3}

Therefore, the probability of choosing a lemon lime or orange is \frac{2}{3}.

8 0
3 years ago
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