Answer:
18.58 moles of Cu
Solution:
Data Given:
Chemical Formula of Tennantite = Cu₁₂As₄S₁₃
Mass of Cu₁₂As₄S₁₃ = 2290 g
M.Mass of Cu₁₂As₄S₁₃ = 1479.06 g.mol⁻¹
Step 1: Calculate Moles of Cu₁₂As₄S₁₃ as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 2290 g ÷ 1479.06 g.mol⁻¹
Moles = 1.548 mol
Step 2: Calculate Moles of Cu,
As,
1 mole of Cu₁₂As₄S₁₃ contains = 12 moles of Cu
So,
1.548 mol of Cu₁₂As₄S₁₃ will contain = X moles of Cu
Solving for X,
X = (1.548 mol × 12 mol) ÷ 1 mol
X = 18.58 moles of Cu
Answer:
D
Explanation:
beacause all the elements in period 3 has different valence electrons hence you look at the first element in period 3 is sodium which has a valence electron of 1 when you go across the period to the right their valence electron decreases to be negative
Reaction
2AgNO₃ + Cu ⇒ Cu(NO₃)₂ + 2Ag
mol silver (Ag): 95.3 : 108 g/mol = 0.882
mol copper nitrate (Cu(NO₃)₂): 82.9 : 187.5 g/mol = 0.441
mol Ag = 2 x mol Cu(NO₃)₂, so 0.441 being the mole basis of the reactants
mol Cu = 0.441
mass Cu = 0.441 x 63.5 g/mol = 28 g
mol AgNO₃ = 0.882
mass AgNO₃ = 0.882 x 170 g/mol = 149.94 g
For the answer to the question above,
The re<span>action of solid iron with aqueous copper sulfate is an example of a single displacement type of reaction which exchanges only the cations of the element and the compound. In this case, the equation is
Fe (s) + CuSO4 (aq) = FeSO4 + Cu (s) </span>