Answer:
Theoretical yield is 10.0g of HF.
Explanation:
Theoretical yield is defined as the yield of a reaction assuming a 100%.
In the reaction:
SiF₄(s) + 2H₂O(l) → 4HF(aq) + SiO₂(s)
2 moles of water produce 4 moles of HF.
4.51g of H₂O are:
4.51g ₓ (1mol/18.02g) = 0.250moles of water. Moles of HF:
0.250moles H₂O ₓ (4mol HF/2mol H₂O) = 0.500mol HF
In grams:
0.500mol HF ₓ (20.01g / 1mol) = <em>10.0g of HF - theoretical yield-</em>
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I hope it helps!
The mole fraction of the 2.2 molal solution whose solvent is naphthalene is 0.28.
Using the relation;
molality = mole fraction × 1000/MA
Where MA = molar mass of the solvent
We know from the question that the molaity of the solution is 2.2 molal
Making the mole fraction the subject of the formula;
mole fraction = molality × MA/1000
MA = 128 g/mol
mole fraction = 2.2 × 128/1000
Mole fraction = 0.28
Learn more: brainly.com/question/2510654
There are 5 protons in Boron 1.
12 moles H
2
O
Explanation:
Your tools of choice for stoichiometry problems will always be the mole ratios that exist between the chemical species that take part in the reaction.
As you know, the stoichiometric coefficients attributed to each compound in the balanced chemical equation can be thought of as moles of reactants needed or moles of products formed in the reaction.
In your case, the balanced chemical equation for this synthesis reaction looks like this
2
H
2(g]
+
O
2(g]
→
2
H
2
O
(l]]
Notice that the reaction requires
2
moles of hydrogen gas and
1
mole of oxygen gas to produce
2
moles of water.
This tells you that the reaction produces twice as many moles of water as you have moles of oxygen gas that take part in the reaction.
You know that your reaction uses
6.0
moles of oxygen. Assuming that hydrogen gas is not a limiting reagent, you can say that the reaction will produce
6.0
moles O
2
⋅
2
moles H
2
O
1
moles O
2
=
12 moles H
2
O
hope this helps
o(*°▽°*)o
Over land or over cooler water they start to lose their power