Answer:try to make a good pic please I have ideas about the topic
The molar concentration of the potassium hydroxide solution was 0.815 mol/L.
<em>Balanced equation</em>: 2KOH + H_2SO_4 → K_2SO_4 + 2H_2O
<em>Moles of H_2SO_4</em>:
15.1 mL H_2SO_4 × (1.50 mmol H_2SO_4 /1 mL H_2SO_4)
= 22.65 mmol H_2SO_4
<em>Moles of KOH</em>: 22.65 mmol H_2SO_4× (2 mmol KOH/2 mmol H_2SO_4)
= 45.30 mmol KOH
<em>Concentration of KOH</em>: c= "moles"/"litres" = 45.30 mmol/55.6 mL
= 0.815 mol/L
The CH4 molecule has the lowest molecular weight, so it has the lowest boiling point.
Hope I helped :)
Answer:
Explanation:
Cubic decimeter is the same unit as liter; so, mole per cubic decimeter is mole per liter, and that is the unit of concentration of molarity. Thus, what is asked is the molarity of the solution. This is how you find it.
1. <u>Take a basis</u>: 1 dm³ = 1 liter = 1,000 ml
2. <u>Calculate the mass of 1 lite</u>r (1,000 ml) of solution:
- density = mass / volume ⇒ mass = density × volume
Here, the density is given through the specific gravity
Scpecific gravity = density of acid / density of water
Take density of water as 1.00 g/ml.
- density of solution = 1.25 g/ml
- mass solution = 1.25 g/ml × 1,000 ml = 1,250 g
3. <u>Calculate the mass of solute</u> (pure acid)
- % m/m = (mass of solute / mass of solution) × 100
- 56 = mass of solute / 1,250 g × 100
- mass of solute = 56 × 1,250g / 100 = 700 g
4. <u>Calculate the number of moles of solute</u>:
- moles = mass in grams / molar mass = 700 g / 70 g/mol = 10 mol
5. <u>Calculate molarity (mol / dm³)</u>
- M = number of moles of solute / liter of solution = 10 mol / 1 liter = 10 mol/liter.
In a redox reaction electrons are lost and gained in equal numbers. The species that is oxidized gives electrons to the species that is reduced. I hope this helps. Let me know if anything is unclear.