Answer:
Mg(OH)2 + 2HCI ⇒ MgCI2 + 2H2O
Explanation:
In order to balance a chemical equation you need to make sure both sides of the equations are equal.
Mg(OH)2 + 2HCI = MgCI2 + H2O
Mg = 1
Oh = 2
HCI = 2
Products:
Mg = 1
CI = 2
H = 2
O = 1
2H20 = 1 × 2 = 2
2 × 2 = 4
2HCI
1 × 2 = 2
Mg(OH)2 + 2HCI ⇒ MgCI2 + 2H2O
Hope this helps.
Answer:
Case 1:
X = Any element from Group I
i) H
ii) Li
iii) Na
iv) K
v) Rb
vi) Cs
Y = 1
Case 2:
X = Any element from Group II
i) Be
ii) Mg
iii) Ca
iv) Sr
v) Ba
vi) Ra
Y = 2
Case 3:
X = Any element from Group III
i) B
ii) Al
iii) Ga
iv) In
v) Ti
Y = 3
Explanation:
The general formula given is as follow,
XCly
So, if X has +1 oxidation state, then it will require only one Cl atom with oxidation number -1 to form a neutral compound, therefore, y = 1.
If X has +2 oxidation state, then it will require two Cl atoms with oxidation number -1 to form a neutral compound, therefore, y = 2.
If X has +3 oxidation state, then it will require three Cl atoms with oxidation number -1 to form a neutral compound, therefore, y = 3.
Answer:
The answer to your question is letter d. Sr(ClO₃)₂
Explanation:
Data
Reactants HClO₃ and Sr(OH)₂
This is a neutralization reaction because the reactants are a base (Sr(OH)₂) and an acid (HClO₃).
The products in a neutralization reaction are always water and a salt.
Balanced chemical reaction
Sr(OH)₂ + HClO₃ ⇒ H₂O + Sr(ClO₃)₂
Answer:
Explanation:
2CH₃(CH₂)₆CH₃ + 25O₂ = 16CO₂ + 18H₂O.
2 moles 25 moles 18 moles
mol weight of octane = 114
72 g of octane = 72 / 114 = .6316 moles
144 g of oxygen = 144 / 32 = 4.5 moles of oxygen.
2 moles of octane reacts with 25 moles of oxygen
.6316 moles of octant will react with 25 x .6316 / 2 moles of oxygen
= 7.895 moles
So oxygen is the limiting reagent
25 moles oxygen produces 18 moles water
4.5 moles of water produces 18 x 4.5 / 25 moles of water
= 3.24 moles of water
= 3.24 x 18 grams of water
= 58.32 grams of water .
