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4 years ago

BRAINLIEST IF ANSWER IN NEXT 5 MIN!!!!

Chemistry

2 answers:

marishachu [46]4 years ago

7 0

Answer: Option (B) is the correct answer.

Explanation:

Elements present in group VII are known as halogens. Elements of group VII are fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (As).

Since, they are same group elements so all of them have seven valence electrons.

Whereas inert gases are the gases present in group 8. These are helium, neon, argon, krypton, xenon, and radon.

Active metals are the substances that readily react with another substance. Elements of group 1 are known as active metals as they have only one valence electron.

Therefore, we can conclude that out of the following the halogen elements are all from Group VII.

creativ13 [48]4 years ago

4 0

Halogen elements are the Group VII on the periodic table.

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shutvik [7]

Answer : The temperature of the chloroform will be, $101.67^oF$

Explanation :

First we have to calculate the mass of chloroform.

$\text{Mass of chloroform}=\text{Density of chloroform}\times \text{Volume of chloroform}=1.4832g/ml\times 74.81ml=110.958g$

conversion used : $(1cm^3=1ml)$

Now we have to calculate the temperature of the chloroform.

Formula used :

$q=m\times c\times (T_{final}-T_{initial})$

where,

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$c$ = specific heat capacity = $0.96J/g.K$

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$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $25^oC=273+25=298K$

Now put all the given values in the above formula, we get:

$1460J=110.958g\times 0.96J/g.K\times (T_{final}-298)K$

$T_{final}=311.706K$

Now we have to convert the temperature from Kelvin to Fahrenheit.

The conversion used for the temperature from Kelvin to Fahrenheit is:

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As we know that, $K=^oC+273$ or, $K-273=^oC$

$K-273=\frac{5}{9}\times (^oF-32)$

$K=\frac{5}{9}\times (^oF-32)+273$ ...........(1)

Now put the value of temperature of Kelvin in (1), we get:

$311.706K=\frac{5}{9}\times (^oF-32)+273$

$T_{final}=101.67^oF$

Therefore, the temperature of the chloroform will be, $101.67^oF$

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3 years ago

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Elan Coil [88]

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3 years ago

Read 2 more answers

What is the change in density if a sample goes from 3.21 g/L to 5.43 g/mL?

Step2247 [10]

Answer:

$\Delta \rho =2.22 g/mL$

Explanation:

Hello,

In this case, since a change in science is widely known to be considered as a subtraction between the the final and initial values of two measured variables and is represented via Δ, here the final density is 5.43 g/mL and the initial one was 3.21 g/mL, therefore, the change in density is:

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Best regards.

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