Answer:
The high-leg voltage is
Explanation:
A diagram showing the arrangement of this three phase transformer is shown on the first uploaded image
The high - leg terminal is in the diagram is from
Generally the high-leg terminal is 1.732 times of the the voltage from line to center tap which is given as 277 V
The high -voltage can be computed as follows
Answer:
Explanation:
Given:
The accelerated energy, U = 1.25 MeV = 1.25 × 10⁶ eV
we know,
1 eV = 1.6 × 10⁻¹⁹ J
thus,
1.25 eV = (1.6 × 10⁻¹⁹) × (1.25) J = 2 × 10⁻¹³ J
Now, Applying the law of conservation of energy, the energy due to acceleration will be equal to the kinetic energy
mathematically,
K.E = U
where,
m = mass of the particle = 1.67 × 10⁻²⁷ kg
v = velocity of the particle
on substituting the values we get
or
or
or
Answer:
1.045 m from 120 kg
Explanation:
m1 = 120 kg
m2 = 420 kg
m = 51 kg
d = 3 m
Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.
By use of the gravitational force
Force on m due to m1 is equal to the force on m due to m2.
3 - y = 1.87 y
3 = 2.87 y
y = 1.045 m
Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.