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3 years ago

Lavoisier made an important contribution to chemistry by _____.

Physics

2 answers:

aniked [119]3 years ago

8 0

By making the law of matter witch is matter can not be made or destored

ira [324]3 years ago

4 0

Developing the law of conservation of matter

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You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to th

geniusboy [140]

Answer:

Part 1

20 N

Part 2

0.4 m/s²

Part 3

4 m/s

Explanation:

The force which pulls the sled right = 50 N

The friction force exterted towards left by the snow = -30 N

The mass of the sled = 50 kg

Part 1

The sum of the forces on the sled, F = 50 N + (-30) N = 20 N

Part 2

The acceleration of the sled is given as follows;

F = m·a

Where;

m = The mass of the sled

a = The accelertion

a = F/m

∴ a = (20 N)/(50 kg) = 0.4 m/s²

The acceleration of the sled, a = 0.4 m/s²

Part 3

The initial velocity of the sled, u = 2 m/s

The kinematic equation of motion to determine the speed of the sled is v = u + a·t

The speed, <em>v</em>, of the sled after t = 5 seconds is therefore;

v = 2 m/s + 0.4 m/s² × 5 s = 4 m/s.

7 0

3 years ago

Which of the examples below is an example of convection?

nasty-shy [4]

Basking in the sun :)

3 0

3 years ago

A mass hangs on the end of a massless rope. The pendulum is held horizontal and released from rest. When the mass reaches the bo

drek231 [11]

Answer:

$T = 37.5 N$

Explanation:

As the pendulum reached to the lowest position then we will have

$T - mg = \frac{mv^2}{L}$

$14.2 - m(9.81) = \frac{m(2.9^2)}{L}$

now when it will reach to the height of the peg then its speed is given as

$v_f^2 - v_i^2 = 2 a d$

so we will have

$v_f^2 - 2.9^2 = 2(-9.81)(\frac{L}{5})$

$v_f^2 = 2.9^2 - 3.924L$

also we know that

$2.9^2 - 0 = 2(9.81)(L)$

$L = 0.43 m$

$m = 0.48 kg$

now we have speed of the pendulum when it reach the same height is given as

$v_f^2 = 2.9^2 - (3.924(0.43)$

$v_f = 2.6 m/s$

Now the tension in the string is given as

$T = \frac{mv_f^2}{\frac{L}{5}}$

$T = \frac{0.48(2.6)^2}{\frac{0.43}{5}}$

$T = 37.5 N$

6 0

4 years ago

A diffraction grating is illuminated simultaneously with red light of wavelength 660 {\rm nm} and light of an unknown wavelength

Tanzania [10]

Answer:

$\lambda = 420 nm$

Explanation:

As we know that position of maximum on the screen in diffraction pattern is given as

$y = (\frac{2N + 1}{2})\frac{\lambda L}{d}$

here we know that

position of third maximum due to red color light and position of fifth maximum of unknown wavelength are same

so we have

$\frac{7 \lambda_r L}{2d} = \frac{11 \lambda L}{2d}$

so we have

$\lambda = \frac{7}{11} \lambda_r$

$\lambda = \frac{7}{11}(660 nm)$

$\lambda = 420 nm$

7 0

4 years ago

Two identical objects A and B fall from rest from different heights to the ground. If object B takes twice as long as object A t

Yuki888 [10]

Answer:

1:4

Explanation:

We have, two identical objects A and B fall from rest from different heights to the ground.

Object B takes twice as long as object A to reach the ground. It is required to find the ratio of the heights from which A and B fell. Let $h_A\ \text{and}\ h_B$ are the height for A and B respectively. So,

$\dfrac{h_A}{h_B}=\dfrac{(1/2)gt_A^2}{(1/2)gt_B^2}\\\\\dfrac{h_A}{h_B}=\dfrac{t_A^2}{t_B^2}$

We have,

$t_B=2t_A$

So,

$\dfrac{h_A}{h_B}=\dfrac{t_A^2}{(2t_B)^2}\\\\\dfrac{h_A}{h_B}=\dfrac{1}{4}$

So, the ratio of the heights from which A and B fell is 1:4.

7 0

3 years ago