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SpyIntel [72]
2 years ago
7

In total, 2 baseballs and 3 footballs cost $67. a football is $4 more than 3 times the cost of a baseball. find the cost of a ba

seball
Mathematics
1 answer:
egoroff_w [7]2 years ago
6 0

The cost of the Baseball is $5.

Lets take football cost as "x"

And taking baseball cost as "y"

According to given conditions,

2y + 3x = 67

x= 3y + 4

Lets put the values of x in equation (1):

2y + 3 (3y+4) = 67

=> 2y + 9y + 12 = 67

=> 11y = 55

y = 5

x = 3(5) + 4

x = 19

Hence the cost of the Baseball is $5.

Learn more about Linear Equation on:

brainly.com/question/19954463

#SPJ4

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a container of candy is shaped like a cylinder and has a volume of 125.6 cubic centimeters. If the heights of the container is 1
Elenna [48]

The radius of the container is 2 centimeter

<h3><u>Solution:</u></h3>

Given that a container of candy is shaped like a cylinder

Given that volume = 125.6 cubic centimeters

Height of conatiner = 10 centimeter

To find: radius of the container

We can use volume of cylinder formula and obatin the radius value

<em><u>The volume of cylinder is given as:</u></em>

\text {volume of cylinder }=\pi r^{2} h

Where "r" is the radius of cylinder

"h" is the height of cylinder and \pi is constant has value 3.14

Substituting the values in formula, we get

\begin{array}{l}{125.6=3.14 \times r^{2} \times 10} \\\\ {r^{2}=\frac{125.6}{31.4}} \\\\ {r^{2}=4}\end{array}

Taking square root on both sides,

r = \sqrt{4}\\\\r = 2

Thus the radius of the container is 2 centimeter

4 0
3 years ago
6 1/2 - 3 2/5 please help really need it
tatuchka [14]
Answer is 3 1/10 


6 1/2 - 3 2/5 =
13/2 - 17/5 =
65/10 - 34/10 = 
31/10 = 3 1/10
4 0
2 years ago
How much longer is the hypotenuse of the triangle than its shorter leg?
RUDIKE [14]

This is an incomplete question, here is a complete question and image is also attached below.

How much longer is the hypotenuse of the triangle than its shorter leg?

a. 2 ft

b. 4 ft

c. 8 ft

d. 10 ft

Answer : The correct option is, (b) 4 ft

Step-by-step explanation:

Using Pythagoras theorem in ΔACB :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(AB)^2=(AC)^2+(BC)^2

Given:

Side AC = 6 ft

Side BC = 8 ft

Now put all the values in the above expression, we get the value of side AB.

(AB)^2=(6)^2+(8)^2

AB=\sqrt{(6)^2+(8)^2}

AB=10ft

Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.

Difference = Side AB - Side AC

Difference = 10 ft - 6 ft

Difference = 4 ft

Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.

5 0
3 years ago
Read 3 more answers
Geometry: please only comment if you know the answer I need help with this please
stich3 [128]

Answer:

Step-by-step explanation:

8 0
2 years ago
Use the substitution method to solve the system of equations. Choose the correct ordered pair. 2x + y = 10 y = x – 5 A. (5, 0) B
erica [24]
It would be A.) (5,0)
8 0
3 years ago
Read 2 more answers
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