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3 years ago

Help ples me i hate ixl

Mathematics

2 answers:

WINSTONCH [101]3 years ago

8 0

Answer:

200

Step-by-step explanation:

Base of the prism is a square

$\\ \tt {:}\longrightarrow Area\:of\:base=(side)^2$

$\\ \tt {:}\longrightarrow (5)^2$

$\\ \tt {:}\longrightarrow 25cm^2$

Now

$\\ \tt {:}\longrightarrow Volume=Area\:of\:Base\times Height$

$\\ \tt {:}\longrightarrow 25\times 8$

$\\ \tt {:}\longrightarrow 200cm^3$

DiKsa [7]3 years ago

3 0

ANSWER:

As we know that,

Volume of triangular prism = 1/2Bh

1/2 × (5)² × 8

1/2 × 25 × 8

100cm³.

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How do I count by twelfths

Korvikt [17]

12, x 1 = 12

12 x 2 =24

12 x 3 = 36

12 x 4 =48

12 x 5= 60

12 x 6 =72

12 x 7 = 84

12 x 8= 96

12 x 9= 108

12 x 10 = 120

12 x 11=132

12x 12= 144

hope this helps

8 0

3 years ago

In the diagram below, point P is circumscribed about quadrilateral ABCD. What is the value of x? (Pls answer I give lot of point

Vlada [557]

Answer:

D. 50

Step-by-step explanation:

130+x=180

x=50

6 0

3 years ago

(6x10^2)/(3x10-5) help what is this in standard form?

Tasya [4]

<u>Answer: </u>

The standard form of $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ is 20,00,0000

<u>Solution: </u>

Given that $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ ---- eqn 1

To write $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ in standard form,

We know that $\bold{\frac{1}{a^{-m}} = a^{m}}$ .So $\frac{1}{10^{-5}}$ becomes $10^{5}$ .

Now eqn 1 becomes,

$= \frac{6 \times 10^{2}}{3} \times 10^{5}$ ----- eqn 2

We know that $\bold{a^{m} \times a^{n}=a^{m+n}}$ , so $10^{2} \times 10^{5} = 10^{7}$

Now eqn 2 becomes,

$= \frac{6}{3} \times 10^{7}$

$= 2 \times 10^{7}$ ---- eqn 3

Expanding $10^{7}$ :

Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

$10^{7} = 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10$

Now eqn 3 becomes,

$= 2 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10$

= 20,00,0000

Hence the standard form of $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ is 20,00,0000

6 0

3 years ago

Which of the follwing regular polygons can make a tessellation?

Elodia [21]

I think it's square and hexagon.

6 0

3 years ago

PLEASE HELP, I REALLY NEED IT!!!

inessss [21]

Let's break this down into what each piece is.

One flat= one whole= 1

One rod= one tenth= 0.1

One unit= one hundredth= 0.01

a) We have 1 flat, 3 rods, and 7 units. Using what we know, we have 1 whole, 3 tenths, and 7 hundredths. So, this is 1 + 0.3+ 0.07. This equals 1.37.

b) 1 flat, 37 units. This is 1 whole, and 37 hundredths. When there are two digits that you want to put in the hundredths place, put the digit furthest to the right in the hundredths place (excluding decimals) and place the rest of the number to the left accordingly. So for us, 37 hundredths would be .37, not .037. Add up 1 and .37, and we have 1.37.

c) 13 rods, 7 units. This is like the last problem. We have two digits wanted to go in the tenths place, but that isn't possible. So, we take the digit all the way to the right and put it in the tenths place (3). Now, we take out remaining digits (1), and put it in the next space to the left. Our rods= 1.3. Now for our units. We have 7, so that equals 0.07. Add it together, and now we have 1.37.

All of the problems equal 1.37. This shows how many ways a number can be represented.

Hope this helped! If it's still confusing, feel free to comment. have a nice day!

4 0

2 years ago