Answer:
y = 6x + 0
Step-by-step explanation:
Equation of a line
y = mx + c
Given
( 0 , 0) ( -1/2 , -3)
find the slope m
m = y2 - y1 / x2 - x1
x1 = 0
y1 = 0
x2 = -1/2
y2 = -3
Insert the values
m = y2 - y1 / x2 - x1
m = -3 - 0 / -1/2 - 0
= -3/-1/2
Minus cancels minus
= 3/1/2
= 3/1 ÷ 1/2
= 3/1 × 2/1
= 6/1
= 6
m = 6
Substitute any of the two points given into the equation of a line
y = mx + c
Where
y - intercept point y
x - intercept point x
m - slope of the line
c - intercept
(-1/2 , -3)
x = -1/2
y = -3
-3 = 6(-1/2) + c
-3 = -6/2 + c
-3 = -3 + c
-3 + 3 = c
c = 0
y = 6x + 0
The equation of the line is
y = 6x + 0
We are supposed to assume FC and AD is straight line
let's find all the angles
you already see the right angle is 90 degrees, you got that right
striaght line is 180 degrees
90+46+EF=180
136+EF=180
minus 136 both sides
EF=44
now we got another straight line
you did get that A F=46 because it is oposite
notice: AB=BC because same angle designition
so now we use
180+46+2AB=360
2AB=134
divide 2
AB=67=BC
AC=134 degrees
CAE=134+46+44=224
ABD=180 since straight line
a. 90
b. 224
c.134
d. 180
Answer:
42 - 6 - 6 - 6 - 6 - 6 - 6 - 6 = 0
or
42 - 7 - 7 - 7 - 7 - 7 - 7 = 0
Y = -3/2x + 4...slope is -3/2
A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So that means the slope we will need is 2/3...see how I flipped the slope and changed the sign.
Now we use y = mx + b....slope(m) = 2/3....(3,9)...x = 3 and y = 9.
Time to sub...we r looking for b, the y intercept.
9 = 2/3(3) + b
9 = 2 + b
9 - 2 = b
7 = b
so the perpendicular equation is : y = 2/3x + 7...but we need it in Ax + By = C form....
y = 2/3x + 7....multiply by common denominator of 3 to get rid of fractions
3y = 2x + 21...subtract 2x from both sides
-2x + 3y = 21....<== ur answer...normally, I would have multiplied this by -1 to make x positive...but that is not an answer choice
