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Whitepunk [10]
3 years ago
6

You decide to play roulette 4 times, each time betting on red. What is the distribution of X, the number of times you win?

Mathematics
1 answer:
aalyn [17]3 years ago
3 0
  <span> 1.
If betting on red, 18/38 = 9/19 chance of winning, so 10/19 chance of losing
Chance of winning 4 times: (9/19)^4 = 6561/130321 =~ 5.034%
Chance of winning 3 times: (9/19)^3 * (10/19) * C(4,1) = 29160/130321 =~ 22.3755%
Chance of winning 2 times: (9/19)^2 * (10/19)^2 * C(4,2) = 48600/130321 =~ 37.2925%
Chance of winning 1 time: (9/19) * (10/19)^3 * C(4,3) = 36000/130321 =~ 27.624%
Chance of winning 0 times: (10/39)^4 = 10000/130321 =~ 76.7336% </span>
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Step-by-step explanation:

1. reg pay: 8.96,week days: 1.5 overtime pay, sat: double pay, sun: triple pay

38 hrs regular pay : 38 * 8.96 = 340.48

15 hrs overtime during week : 15 * 1.5(8.96) = 15 * 13.44 = 201.60

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2 hrs overtime on sunday: 2 * 3(8.96) = 2 * 26.88 = 53.76

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===============================

2. reg pay : 14.60, weekday pay: 1.25,sat pay: 1.5 , sun pay: double

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(c) gross wage : 584 + 551.15 = 1135.15 <==

================================

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