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Lera25 [3.4K]
3 years ago
12

Find dy/dx by implicit differentiation and evaluate the derivative at the given point.

Mathematics
1 answer:
LekaFEV [45]3 years ago
3 0
\tan(5x+y)=5x

Differentiating both sides yields

\sec^2(5x+y)\times\left(5+\dfrac{\mathrm dy}{\mathrm dx}\right)=5
\dfrac{\mathrm dy}{\mathrm dx}=5\cos^2(5x+y)-5

At the point (0,0), you get

\dfrac{\mathrm dy}{\mathrm dx}=5\cos^2(5(0)+0)-5=5-5=0
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The value, V (t), in dollars, of a stock t months after it is purchased is modeled by the following equation.
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:V(t)= 42(1-e ^{1.5t} ) +36 is given value in dollars of a stock in t months after it is purchased.

a) Substitute 1 for t

V(1) = 42(1-e^{-1.5} )+36 \\=67.852\\=67.85

V(12) = V(1) = 42(1-e^{-1.5*12} )+36 \\=77.00

b) Find derivative for V

V'(t) = 42(-1.5) e^{-1.5t} )\\\\=-63e^{-1.5t}

c) When V(t) = 75

V(t)=75= 42(1-e ^{1.5t} ) +36\\1-e ^{1.5t=0.9286\\=-2.639

d) As t tends to infinity, exponent being in negative t tends to 0

So V tends to 42(1-0)+36 = 78

3 0
3 years ago
AC =<br> Round your answer to the nearest hundredth.<br> 5<br> ?<br> 35<br> B
Bingel [31]

Answer:2.87

Step-by-step explanation:sin =opp/hyp

Sin 35=ac/5

Cross multiply

Sin 35 x 5 = ac

0.5736 x 5 =ac

2.868=ac

Ac=2.87

3 0
3 years ago
Factor 2x^2-4x-30 completely
Elza [17]
2x² - 4x - 30
2(x²) - 2(4x) - 2(15)
2(x² - 4x - 15)
4 0
3 years ago
4 out of 9 how many groups can be made?
Len [333]

Answer:

its a combination problem, so in your calculator put 9 nCr 4 and you'll get 126. i hope this helps. :)

Step-by-step explanation:


5 0
4 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
3 years ago
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