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julsineya [31]
3 years ago
11

Part a : solve - vp + 40 < 65 for v .

Mathematics
1 answer:
miskamm [114]3 years ago
6 0

Answer:

\large \text{Part a:}\\\\for\ d-\dfrac{25}{d}}

\large\text{Part b:}\\\\\boxed{r=\dfrac{7}{3}w-5}

Step-by-step explanation:

\text{Part a}\\\\-vp+400,\ \text{then}\ \boxed{v>-\dfrac{25}{d}}\\\\\text{if}\ d

\text{Part b}\\\\7w-3r=15\qquad\text{subtract 7w from both sides}\\\\-3r=-7w+15\qquad\text{divide both sides by (-3)}\\\\\boxed{r=\dfrac{7}{3}w-5}

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Solve for v pls thanks
Ksivusya [100]

Answer:

v = 18

Step-by-step explanation:

8/3v = 48

were going to have to get 3 on the other side, so were going to cancel it out and multipliy it because it is a fraction

now we would have 8v = 48*3

48*3=144

now the equation looks like this 8v = 144

to isolate v we can divide 8 on both sides

which brings us to v = 18

High Hopes^^

Barry-

7 0
3 years ago
11 The sides of two similar triangle are in a ratio of 5:6. The area of the larger triangle is 108.
Elodia [21]

Answer:

The area of the smaller triangle is 75.

Step-by-step explanation:

Here, the ratio of the sides of the similar triangle are 5 : 6

The area if the larger triangle = 108

let us assume that the area of the smaller triangle = m

By the Theorem:

In two similar triangles, the ratio of the areas of similar triangles is the square of the ratio of their sides.

Similarly, here

[tex](\frac{5}{6}) ^2  = \frac{m}{108}[/tex]

⇒\frac{(5)^2}{(6)^2}   = \frac{m}{108}

or, \frac{25}{36}   = \frac{m}{108}  \implies m = \frac{108 \times 25}{36}  = 75

⇒ m = 75

Hence, the area of the smaller triangle is 75.

6 0
3 years ago
Please help, brainliest, thanks, five star
AnnZ [28]

Answer:

<u>2(3x + 4)</u>

Step-by-step explanation:

2 x 3x = 6x and 2 x 4 = 8

7 0
2 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
Write and solve a system of equations for this question please
andre [41]
Let b and s be the velocity of the boat and stream respectively....

3(b-s)=27

b-s=9

b=9+s  we will use this in the second equation....

2(b+s)=30

b+s=15, now use b found above in this to get:

9+s+s=15

2s+9=15

2s=6

s=3, and since from earlier b-s=9, b=9+s so

b=12

So the speed of the boat is 12mph and the stream is 3 mph
6 0
3 years ago
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