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julsineya [31]
3 years ago
11

Part a : solve - vp + 40 < 65 for v .

Mathematics
1 answer:
miskamm [114]3 years ago
6 0

Answer:

\large \text{Part a:}\\\\for\ d-\dfrac{25}{d}}

\large\text{Part b:}\\\\\boxed{r=\dfrac{7}{3}w-5}

Step-by-step explanation:

\text{Part a}\\\\-vp+400,\ \text{then}\ \boxed{v>-\dfrac{25}{d}}\\\\\text{if}\ d

\text{Part b}\\\\7w-3r=15\qquad\text{subtract 7w from both sides}\\\\-3r=-7w+15\qquad\text{divide both sides by (-3)}\\\\\boxed{r=\dfrac{7}{3}w-5}

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Order the following numbers from least to greatest. Put the lowest number on the left. 2 -2 5 -5
natulia [17]

Answer:

-5,-2,2,5

Step-by-step explanation:

5 0
3 years ago
You have decided to purchase a car for $22,346.16. The credit union requires a 10% down payment and will finance the
sukhopar [10]

Answer:

(b) \$24,169.60

Step-by-step explanation:

Given:  Cost of car is \$22,346.16

            Sales tax is 7.6\%    

             The license and title  charges are \$125.13

To find: The amount that the credit union will finance.

Solution:

We have,  

Cost of car=\$22,346.16  

Sales tax is 7.6\% of \$22,346.16

Therefore,  

sales tax =\frac{7.6}{100}\times22,346.16=\$1698.31

The license and title  charges =\$125.13

Now, the amount that the credit union will finance is

cost of car+sales tax+the license and title  charges

=\$22346.16+\$1698.31+\$125.13

=\$24,169.60

Hence, the amount that the credit union will finance is \$24,169.60.

So, (b) \$24,169.60 is correct.

5 0
3 years ago
Read 2 more answers
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.3. (Round your ans
Maurinko [17]

Answer:

0.0039 is the probability that the sample mean hardness for a random sample of 12 pins is at least 51.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 50

Standard Deviation, σ = 1.3

Sample size, n = 12

We are given that the distribution of hardness of pins is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{1.3}{\sqrt{12}} = 0.3753

P(sample mean hardness for a random sample of 12 pins is at least 51)

P( x \geq 51) = P( z \geq \displaystyle\frac{51 - 50}{0.3753}) = P(z \geq 2.6645)

= 1 - P(z < 2.6645)

Calculation the value from standard normal z table, we have,  

P(x \geq 51) = 1 - 0.9961= 0.0039

0.0039 is the probability that the sample mean hardness for a random sample of 12 pins is at least 51.

3 0
3 years ago
Does anyone know this?
Darina [25.2K]

2 x 2 x 2 x 3

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3 years ago
An 11 letter word for the variable in an algebraic expression
Natalija [7]
I'm just guessing but maybe expressions
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