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zmey [24]
3 years ago
14

Helene claimed that the expected value when rolling a fair die was 3.5. Steve said that wasn't possible. He said that the expect

ed value was the most likely value in a single roll of the die, and since it wasn't possible for a die to turn up with a value of 3.5, the expected value couldn't possibly be 3.5. Who is right
Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0

Answer:

Helene is right

Step-by-step explanation:

Mathematically, the expected values is defined as the sum of all the possible outcomes that an event can have times the probality of the respective outcome:

x = ∑ p *i,

where x is the expected value, i represents every outcome that can occur, and p is the probability of said outcome.

Now, for the case of a dice, the expected value would be:

x = 1 * \frac{1}{6} + 2 * \frac{1}{6} + 3 * \frac{1}{6} + 4 * \frac{1}{6} + 5* \frac{1}{6} + 6 * \frac{1}{6},

as every outcome has the same chance of happenning. Solving we get that:

x= \frac{1}{6} *(1 +2 +3 +4+5+6) = \frac{1}{6} * 21 = 3.5

Helene is right.

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