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SCORPION-xisa [38]
3 years ago
14

3x + ky = 8

Mathematics
1 answer:
sattari [20]3 years ago
4 0

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

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Write the equation for a line that passes through the point (-8,2) and is parallel to 5x-4y=4. Enter your equation in slope inte
Lana71 [14]

Answer:

y = 5/4x + 12

Step-by-step explanation:

5x - 4y = 4

-4y = -5x + 4

y = (-5x + 4)/-4

y = 5/4x - 1

Parallel Slope ---> m = 5/4

(-8, 2)

y = mx + b

2 = 5/4(-8) + b

2 = 5 * -2 + b

2 = -10 + b

12 = b

b = 12

y = 5/4x + 12      <---- This is the answer

Hope this helps!

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2 years ago
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Answer:

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4 0
3 years ago
Hellppp 70 pointsss
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y=a.(X-x1)(X-x2)

x1 and x2 are x-intercepts

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7 0
2 years ago
given a right-angled triangle with perimeter 18. The sum of the squares of the three side lengths is 128. What is the area of th
ahrayia [7]

Answer:

9units²

Step-by-step explanation:

A triangle has 3 sides. Let the length of the three sides be a, b, c.

If the perimeter of the triangle is 18, then;

P = a+b+c

a+b+c = 18... 1

If the sum of the squares of the three side lengths is 128, this means;

a²+b²+c² = 128... 2

Since the triangle is also right angled, according to Pythagoras theorem;

c² = a²+b²... 3 (taking c as the hypotenuse)

Substitute equation 3 into 2;

(a²+b²)+c² = 128

c²+c² = 128

2c² = 128

c² = 128/2

c² = 64

c = √64

c = 8

Substituting c = 8 into 1

a+b+c = 18

a+b+8=18

a+b = 10 ...... 3

Substituting c = 8 into 2

a²+b²+c² = 128

a²+b²+8² = 128

a²+b²+64 = 128

a²+b²= 64..... 4

Solve equation 3 and 4 simultaneously;

a+b = 10

a²+b²= 64

From 4; a = 10-b

Substitute a = 10-b into 4;

(10-b)²+b² = 64

100-20b+b²+b² = 64

2b²-20b+100-64 = 0

2b²-20b+36 = 0

Divide through by 2:

b²-10b+18 = 0

b = 10±√10²-4(18)/2

b = 10±√100-72/2

b =( 10±√28)/2

b =(10±√4×7)/2

b = (10±2√7)/2

b = 5±√7

Hence b = 5+√7

If a+ b = 10

a+(5+√7 ) = 10

a = 10-(5+√7)

a = 10-5-√7

a = 5-√7

Area of the triangle A = 1/2 ab

A = 1/2 × (5+√7) × (5-√7)

A = 1/2 × (25-5√7+5√7-7)

A = 1/2 × (25-7)

A = 1/2 × 18

A = 9

Hence the are of the triangle is 9units²

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3 years ago
In Relation to my last question
likoan [24]
You could not use as much as your using or save more to have more.
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