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stepladder [879]
3 years ago
9

How do you prove theorems behind two parallel lines cut by a transversal?

Mathematics
1 answer:
LenaWriter [7]3 years ago
5 0
The way to do it can be explained like this:
Say AB and CD are the two parallel lines cut by a transversal at E and F respectively.
 Then the pairs of alternate interior angles are:
Angle(AEF) and Angle(DFE)
Angle(CFE) and Angle(BEF)
Now lets prove if this is true:
<span>Angle(CFE) +Angle(DFE) = 180
(linear pair)
Also
Angle(CFE) +Angle(AEF) = 180
(Corresponding angles)
</span><span>Equate the above results:
Angle(CFE) +Angle(DFE) = Angle(CFE) +Angle(AEF)
</span><span>Angle(DFE) = Angle(AEF)
</span>Happens the same with
<span>Angle(CFE) = Angle(BEF)
</span>Hope this is very useful for you

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When a number decreased by 10% the result in 63. What is the number?
Ugo [173]
The number is 69.3 because percent means 0.01, so 10 x 0.01 = 1.1
so 1.1 x 63 = 69.3. you can also do 63 x 10% = 69.3.
4 0
3 years ago
Help me please idk how to do this
Tems11 [23]

Answer: your answer would be B

- 5 over 9

Step-by-step explanation:

3 0
3 years ago
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The function f(x) is shown on the graph.
Sever21 [200]

The value of f(0) is 12.

<h3>What is graph?</h3>

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

By considering the graph we have to find f(0) which means we have to find that point where x- coordinate is zero.

Also, which shows that 12 the function f(x)

So, taking the point is (0,12) we can get f(0)= 12.

Learn more about this concept here:

brainly.com/question/16608196

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7 0
2 years ago
What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.
skad [1K]

Answer:

option A and B

x=\frac{-7+\sqrt{17}} {4}

and

x=\frac{-7-\sqrt{17}} {4}

Step-by-step explanation:

we have

2x^2+7x+4=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^2+7x+4=0

so

a=2\\b=7\\c=4

substitute in the formula

x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}

x=\frac{-7\pm\sqrt{17}} {4}

so

x=\frac{-7+\sqrt{17}} {4}

and

x=\frac{-7-\sqrt{17}} {4}

7 0
2 years ago
(-6, 1) and 3, 5)<br> M= rise/run=(y2-y1)/(x2-x1)
Sergeeva-Olga [200]

Answer:

4/9

Step-by-step explanation:

The slope of these points would be: (5-1)/(3+6) = 4/9

7 0
2 years ago
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