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2 years ago

6

Will give brainliest for correct answer

1 answer:

d1i1m1o1n [39]2 years ago

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Burt is thinking about a career in publishing but does not like writing. What

cricket20 [7]

C. So he can find a job that doesn’t include writing

6 0

3 years ago

Read 2 more answers

Ms. Ache is paid $1250 per week but is fined $100 each day she is late to work. Ms. Ache wants to make at least $3,000 over the

faust18 [17]

She can have 7 days off at most because 3 X 1250 = 3750 - 700 = 3050

7 0

3 years ago

On the coordinate plane below, Point P is located at (2,-3), and point Q is located at (-4,4).

Semenov [28]

Answer:

Approximately 9 units.

Step-by-step explanation:

To find the distance between two ordered pairs, we can use the distance formula. The distance formula is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let (2,-3) be x₁ and y₁ respectively, and let (-4,4) be x₂ and y₂, respectively.

$d=\sqrt{(-4-2)^2+(4--3)^2} \\d=\sqrt{(-6)^2+(7)^2} \\d=\sqrt{36+49} \\d=\sqrt{85}\approx9$

7 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago

hey i know this may be a lame question but can anyone help me how can i multiply 16 with 3,142 (with steps) ?? :/

vovangra [49]

Answer:

50272

Step-by-step explanation:

Okay how I solve these equations is I take the problem apart like this:

3142 = 3000 + 100 + 40 + 2

Now we multiply each number by 16:

3000 * 16 = 48000

100 * 16 = 1600

40 * 16 = 640

2 * 16 = 32

Then we add all the totals together:

48000 + 1600 + 640 + 32 = 50272

Hope this Helps ;)

8 0

2 years ago