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kotegsom [21]
3 years ago
5

How do you find the area of the base in a cylinder

Mathematics
1 answer:
Llana [10]3 years ago
6 0

Answer:

area is easy because its always the  Length times the Width of something  so after you get the area you times it by the base which is the bottom part of the cylinder

Step-by-step explanation:

so you would just get the length and the Width and multiply them and... theres your answer!

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HELP ME PLEASE HELP ME HELP ME PLEASE
riadik2000 [5.3K]

Answer:

<h2>     no, because the remainder is 126</h2>

Step-by-step explanation:

if x+3 is a factor, then -3 is a root of expression, and the remainder would be 0

calculating remainder:

-3(-3)^3+6(-3)^2+6(-3)+9=-3\cdot(-27)+6\cdot9-18+9=\\\\=81+54-9=126

4 0
3 years ago
Choose a room in your home. Suppose small lights are going to be hung from one corner of this room to the opposite corner across
Natalka [10]

Answer:

Bed Room

Step-by-step explanation:

You can see what shape the room is.

But you cant awnser this because it has no visual work to use

3 0
3 years ago
If the area of triangle ABC= 25 square feet, then the area of the rectangle ABCD is:
UkoKoshka [18]
A rectangle has 2 triangle
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5 0
4 years ago
Read 2 more answers
I need help with some grade 10 math it's on slope I have attached a photo
Gala2k [10]

Answer:

a) (1,1)

b) 2/3

I think this is correct

3 0
3 years ago
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QUESTIONS BELOW NEED ANSWER ASAP PLSSS
Crazy boy [7]
It’s B, because VKQ is equal to DKJ. VKQ is 153°, which makes DKJ 153°. But you’re trying to find DKM, which is 153°(the total degree) minus MKJ, the other half not including the one you’re trying to find. But we see a square there, a right angle, meaning that MKJ is equal to 90°

So we take the total of DKM (153°) and subtract it by the half that we know (which is MKJ, 90°) in order to find the half that we don’t know (DKM)

So it’s simply 153-90, which is 63°, so the answer should be B.

Hope this helped if you have other questions regarding this let me know! I know it seems a little confusing
5 0
3 years ago
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