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Answer:
$43
Step-by-step explanation:
You have to find how much he is paying for his games and how much he is paying for his rides, then add them together.
5(3) = $15 (games)
8(3.5) = $28 (rides)
28+15 = 43
Answer:
The value of q and p is 4 and -24 respectively.
Step-by-step explanation:
Being 
, the line x=4 is a vertical asymptote to the graph of f(x). The line r is an asymptote of a function if the graph of the function is infinitely close to the line r. That is, an asymptote is a line to which a function approaches indefinitely, without ever touching it.
Being a rational function that which can be expressed as the quotient of two polynomials, a vertical asymptote occurs when the denominator is 0, that is, where the function is not defined. In this case:
x - q= 0
Solving:
x= q
Being the line x=4 the vertical asymptote, then
<u><em>4=q</em></u>
Then the function f (x) is:
The y intercept is (0,4). This is, x= 0 and y=4. Replacing:
Solving:
4*(-4)= p+8
-16= p+8
-16 - 8= p
<u><em>-24= p</em></u>
<u><em>The value of q and p is 4 and -24 respectively.</em></u>
Answer and Explanation:
A function is said to be increasing, if the derivative of function is f’(x) > 0 on each point. A function is said to be decreasing if f”(x) < 0.
Let y = v (z) be differentiable on the interval (a, b). If two points z1 and z2 belongs to the interval (a, b) such that z1 < z2, then v (z1) ≤ v (z2), the function is increasing in this interval.
Similarly, the function y = v(z) is said to be decreasing, when it is differentiable on the interval (a , b).
Two points z1 and z2 Є (a, b) such that z1 > z2, then v (z1) ≥ v(z2). The function is decreasing on this interval.
The function y = v (z)
The derivative of function Y’ = v’(z) is positive, then the function is increasing.
The function y = v (z)
The derivative of function y’ is negative, then the function is decreasing.
