The answer will be 40. As it doubles twice during 220mins- 10 to 20 and then 20 to 40.
Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.
<h3>How to find the width and length?</h3>
First, find the area of the pool:
= Length x Width
= 10 x 26
= 260 meters ²
The area of the path can therefore be found to be:
= Total area of pool and path combined - Area of pool
= 1,092 - 260
= 832 meters²
Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path
= √832
= 28.8
In conclusion, the width and length of the path are 28.8 meters.
Find out more on combined area at brainly.com/question/12966430
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diagonal is sqrt of (s^2 x 2)
8^2 = 64
64*2 = 128
sqrt(128) = 11.3137
round answer as needed
Answer:
53 54 55
Step-by-step explanation:
Consecutive Integers are integers that go one after the other unless explained otherwise, so 53, 54 and 55 add up to 162.
