WHAT ARE 4 CONDITONS FOR FOSSILIZATION PLEASE AND THANK U

Biology

1 answer:

mote1985 [20]3 years ago

3 0

Answer:

Preservation of remains (protection against scavenging, erosion and environmental damage) High pressure to promote mineralisation of remains (i.e. turn hard body parts into fossilised rocks) Anoxic (low oxygen) conditions to protect against oxygen damage and prevent decomposition by saprotrophs

Explanation:

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A research team studies a large Eastern Milk Snake population in a metropark. In these snakes, gene T is one gene that affects t

sweet [91]

Answer:

Option E

Explanation:

As per Hardy Weinberg's second equation of equilibrium, the sum of genotype frequency for all possible genotype in a given population with two allele is equal to

$p^2 + q^ 2+2pq = 1\\$

Substituting the given values in above equation, we get -

$0.16 + 0.64 + 0.20 =1\\ p^2+q^2+2pq= 1$

Hence, second equation satisfies.

As per Hardy Weinberg's first equation of equilibrium, sum of all allele frequencies is equal to 1

$p + q=1\\\sqrt{0.16} +\sqrt{0.64} \\0.4+0.8 = 1.2\neq 1$

Hence, this population is not in Hardy weinberg's equation.

After one generation, the frequency of T allele is $0.4$ which is the same as that of frequency of T allele in previous generation

Also as per hardy Weinberg's theory , if a population genotype frequency sums up to 1, it is in equilibrium if its allele frequency sum is also 1.

But here in 2004. This was not the case.

However, Weinberg has stated that the population which is not in equilibrium can reach equilibrium after one generation only with a new set of genotype frequency and allele frequencies.

Hence, in this case there is a possibility that allele and genotype frequencies have readjusted to sum up to 1

If frequency of the T allele is $0.4$

New frequency of the t allele would be

$1- 0.4\\= 0.6$