Question

Two particles with the same charges are held a fixed distance apart. The charges are equal in magnitude and they exert a force on each other. Half of one of the charges is transferred to the other charge and the distance is unchanged. What happens to the force exerted by one charge on the other charge? The force is half as large The force is uncharged The force is twice as large The force is one fourth as large The force is three fourths as large

Answer 1

Answer:

The force is three fourth as large of initial force

Explanation:

Let assume that that charge on each particle be q and the distance which is fixed between them be r.

Then By using Coulombs law the force$F_1$between them  is

$F_1=\dfrac{q^2}{4\pi \epsilon_0 r^2}$

When half of the charge is transferred from on to other particle then the charge on the particles are 0.5 q and 1.5 q

Let the force between them be $F_2$

$F_2=\dfrac{0.5 q\times 1.5 q}{4\pi \epsilon_0 r^2}$

$F_2=\dfrac{3q^2}{4\pi \epsilon_0 4r^2}$

Then it can can be seen from taking taking ratio that $\dfrac{F_2}{F_1}=\dfrac{3}{4}$