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2 years ago

Which biome would you not find trees or deep rooted plants in ?

Physics

2 answers:

pogonyaev2 years ago

8 0

Answer: 5. Tundra

Explanation:

Tundra is a biome that is located in the coldest regions of the world. This is characterized by short growing seasons and low temperatures. The plants growing in these regions are short perennials. The soil in these regions is frozen and nutrition poor. Therefore, plants growing here are simple like lichens, mosses, sedges, grasses and dwarf woody plants as the soil and weather conditions cannot support the growth of deep rooted plants and trees.

Dafna1 [17]2 years ago

6 0

The tundra because it's growing season is too short.

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A certain ultrasound device can measure a fetal heart rate as low as 50 beats per minute. This corresponds to the surface of the

balu736 [363]

Answer:

The. Machine must detect a shift of

1 Hz

Explanation:

Frequency shift is given as

={ ( Vsound +V/ V sound -V) -1}f emitted

So by substitution we have

= { 1540+4E-4/1540-4E)-1) 2*10^6

= 1Hz

7 0

3 years ago

A small artery has a length of 1.10 × 10-3 m and a radius of 2.50 × 10-5 m. If the pressure drop across the artery is 1.15 kPa,

levacccp [35]

Answer:

$7.69533\times 10^{-11}\ m^3/s$

Explanation:

P = Pressure difference = 1.15 kPa

r = Radius = $2.5\times 10^{-5}\ m$

$\eta$ = Viscosity of liquid = $2.084\times 10^{-3}\ Pas$

l = Length of artery = $1.1\times 10^{-3}\ m$

From Poiseuille's equation we have

$Q=\frac{\pi Pr^4}{8\eta l}\\\Rightarrow Q=\frac{\pi 1.15\times 10^3\times (2.5\times 10^{-5})^4}{8\times 2.084\times 10^{-3}\times 1.1\times 10^{-3}}\\\Rightarrow Q=7.69533\times 10^{-11}\ m^3/s$

The flow rate of blood is $7.69533\times 10^{-11}\ m^3/s$

8 0

2 years ago

What would the speed of this wave be?

valentinak56 [21]

Answer:

c) 100,000 m/s

Explanation:

You need to take the same wave length from the top graph and bottom one, so let's take half a wave length then in the top one that is 0.005, but in the bottom one it's 2000/4 = 500 because they are smaller and there are 4 half waves before you get to 2000, whereas in the top one there is 1 half wave before you get to 0.005 on the graph.

Now use speed = distance / time

speed = 500 / 0.005 = 100 000 m/s

7 0

3 years ago

A car is driving around a banked curve, with the road surface at an angle of 10.0º. If the radius of curvature of the road is 30

IRISSAK [1]

Answer:

maximum speed 56 km/h

Explanation:

To apply Newton's second law to this system we create a reference system with the horizontal x-axis and the Vertical y-axis. In this system, normal is the only force that we must decompose

sin 10 = Nx / N

cos 10 = Ny / N

Ny = N cos 10

Nx = N sin 10

Let's develop Newton's equations on each axis

X axis

We include the force of friction towards the center of the curve because the high-speed car has to get out of the curve

Nx + fr = m a

a = v2 / r

fr = mu N

N sin10 + mu N = m v² / r

N (sin10 + mu) = m v² / r

Y Axis

Ny -W = 0

N cos 10 = mg

Let's solve these two equations,

(mg / cos 10) (sin 10 + mu) = m v² / r

g (tan 10 + μ / cos 10) = v² / r

v² = r g (tan 10 + μ / cos 10)

They ask us for the maximum speed

v² = 30.0 9.8 (tan 10+ 0.65 / cos 10)

v² = 294 (0.8364)

v = √(245.9)

v = 15.68 m / s

Let's reduce this to km / h

v = 15.68 m / s (1 km / 1000m) (3600s / 1h)

v = 56.45 km / h

This is the maximum speed so you don't skid

7 0

2 years ago

Question 4 (1 point)

djverab [1.8K]

Answer:

directly proportional.

Explanation:

Coulomb's has the formular :

F = kQ₁Q₂ / d²

from the formular F = force

also from the formular Q = charge

hence, from the equation above, force and charge are directly related.so if the charge doubles, the force exerted by it on another charge also doubles because they are directly proportional.

5 0

2 years ago