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gogolik [260]
2 years ago
10

2) ____ AgNO3 + ____ Cu ____ Cu(NO3)2 + ____ Ag

Physics
1 answer:
chubhunter [2.5K]2 years ago
4 0

2) Single replacement (Substitution)

3) single replacement

4) double replacement

5) synthesis

6) decomposition

7) single replacement

8) synthesis

9) double replacement

10) synthesis

11) single replacement

12) synthesis

<em><u>srry for taking a long time hope this helps ^^</u></em>

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the maximum displacement of an oscillatory motion is A=0.49m. determine the position x at which the kinetic energy of the partic
kipiarov [429]

Answer:0.4 m

Explanation:

Given

Maximum displacement A=0.49

The sum of kinetic and elastic potential energy is \frac{1}{2}kA^2

where k=spring constant

U+K.E.=\frac{1}{2}kA^2

when K.E.=U/2

K.E.=kinetic energy

U=Elastic potential Energy

\rightarrow \ U+\frac{U}{2}=\frac{1}{2}KA^2\\\rightarrow \ \frac{3U}{2}=\frac{1}{2}KA^2\\\rightarrow \ U=\frac{1}{3}KA^2\\\rightarrow \ \frac{Kx^2}{2}=\frac{1}{3}KA^2\\\\x=\sqrt{\frac{2}{3}}A\\x=0.4\ m

3 0
3 years ago
Physics conversion <br> Convert 300 cm/min^2 into m/s^2 <br> Please give a thorough explanation!
ANTONII [103]

Answer:

8.33×10⁻⁴ m/s²

Explanation:

There are 100 cm in 1 m, and 60 s in 1 min.

300 cm/min² × (1 m / 100 cm) × (1 min / 60 s)² = 8.33×10⁻⁴ m/s²

6 0
2 years ago
Two forces act on an object. The first force has a magnitude of 17.0 N and is oriented 48.0° counterclockwise from the x ‑axis,
Ivanshal [37]

Answer:

Fn: magnitude of the net force.

Fn=30.11N , oriented 75.3 ° clockwise from the -x axis

Explanation:

Components on the x-y axes of the 17 N force(F₁)

F₁x=17*cos48°= 11.38N

F₁y=17*sin48° = 12.63 N

Components on the x-y axes of the  the second force(F₂)

F₂x= −19.0 N

F₂y=   16.5 N

Components on the x-y axes of the net force (Fn)

Fnx= F₁x +F₂x= 11.38N−19.0 N= -7.62 N

Fny= F₁y +F₂y= 12.63 N +16.5 N = 29.13 N

Magnitude of the net force.

F_{n} =\sqrt{(F_{nx})^{2} +(F_{ny}) ^{2} }

F_{n} =\sqrt{(-7.62)^{2} +(29.13) ^{2} }

F_{n} = 30.11N

Direction of the net force (β)

\beta =tan^{-1} (\frac{29.13}{7.62} )

β=75.3°

Magnitude and direction of the net force

Fn= 30.11N , oriented 75.3 ° clockwise from the -x axis

In the attached graph we can observe the magnitude and direction of the net force

6 0
2 years ago
Turn the ignition switch to start and release the key immediately or you could destroy the______________.
vredina [299]

Starter

Explanation:

Turn the ignition switch to start and release the key immediately or you could destroy the starter.

The car starter is used to cause ignition in the internal combustion engine in order to fire the piston and cause mechanical motion. The starter is used to start the cyclic process of the internal combustion engine.

  • Once the engine starts by igniting the starter, it is best to release it.
  • The starter ensures that the spark plug is engaged and the motor is brought into work.
  • If the ignition is still engaged, the process continues repeatedly and it can damage the starter of the car.

learn more:

Automobile brainly.com/question/2599962

#learnwithBrainly

5 0
3 years ago
"What is the magnifying power of an astronomical telescope using a reflecting mirror whose radius of curvature is 5.9 m and an e
notka56 [123]

Answer:

The Magnifying power of a telescope is M = 109.26

Explanation:

Radius of curvature R = 5.9 m = 590 cm

focal length of objective f_{objective} = \frac{R}{2}

⇒ f_{objective} = \frac{590}{2}

⇒ f_{objective} = 295 cm

Focal length of eyepiece f_{eyepiece} = 2.7 cm

Magnifying power of a telescope is given by,

M = \frac{f_{objective} }{f_{eyepiece} }

M = \frac{295}{2.7}

M = 109.26

therefore the Magnifying power of a telescope is M = 109.26

4 0
3 years ago
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