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Kryger [21]
3 years ago
5

Geoffrey is evaluating the expression (-3^3(2^6)/(-3^5(2^2) what are the values of a,b,c and d

Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0
-9×36÷-15×4
-324÷60
-5.4
(not sure if this is what you are looking for)
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Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
2 years ago
Label the points, lines, and planes to show AB←→ and line j perpendicular to each other in plane R at point A, AB←→ both perpend
algol [13]

Answer:

That would be c

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2 years ago
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What is 2.4×10 to the seventh power
kotykmax [81]
This is easy once you look at it you just have to move the decimal 7 places and you'll get 24,000,000
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TRUE or FALSE?<br><br> 1.) If x = -3, then the value of 4x + 5 is 17.
Strike441 [17]
<h2>I think it's <u>false</u></h2>

<h2><u><em>I</em><em> </em><em>hope</em><em> </em><em>it's</em><em> </em><em>helpfull </em><em>for</em><em> you</em></u></h2>
8 0
3 years ago
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Solve each equation for m -5 =8
Diano4ka-milaya [45]

Answer:

m = 13

Step-by-step explanation:

Given

m - 5 = 8 ( isolate m by adding 5 to both sides of the equation )

m = 8 + 5 = 13

3 0
3 years ago
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