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Firdavs [7]
3 years ago
8

ANSWER ASAP PLEASE!!!!!!!!!!!!!

Mathematics
2 answers:
stich3 [128]3 years ago
7 0

Answer:

It is extremely easy. You just have to substitute the function value of variable "x" back into the original expression to directly obtain the answer for a specific "set value" for a variable of "x". Here they have asked for function of "x" and replaced the function for variable "x" to a value.

For the first one. The function of "x" is replaced by the value of "5". Substitute this value into the original functional expression to obtain the answer. So:

1)

2)

3)

The final answers are given and we can deduce the options for those three questions.

1) Option C) 14.

2) Option C) 2.

3) Option C) 9.

Hope it helps.

Step-by-step explanation:

avanturin [10]3 years ago
3 0
It is extremely easy. You just have to substitute the function value of variable "x" back into the original expression to directly obtain the answer for a specific "set value" for a variable of "x". Here they have asked for function of "x" and replaced the function for variable "x" to a value.

For the first one. The function of "x" is replaced by the value of "5". Substitute this value into the original functional expression to obtain the answer. So:

1) \mathbf{Since, \: f(x) = 4x - 6}

\mathbf{\therefore \quad f(5) = 4 \times 5 - 6}

\mathbf{f(5) = 20 - 6}

\boxed{\mathbf{\therefore \quad Final \: \: Answer, \: f(5) = 14}}


2) \mathbf{Since, \: g(x) = x - 7}

\mathbf{\therefore \quad g(5) = 5 - 7}

\boxed{\mathbf{\therefore \quad Final \: \: Answer, \: g(5) = 2}}


3) \mathbf{Since, \: g(x) = x^2}

\mathbf{\therefore \quad g(3) = 3^2}

\boxed{\mathbf{\therefore \quad Final \: \: Answer, \: g(3) = 9}}


The final answers are given and we can deduce the options for those three questions.


1) Option C) 14.

2) Option C) 2.

3) Option C) 9.


Hope it helps.
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As you can see I keep getting questions wrong.... Can you answer the last question?
aivan3 [116]

Answer:

  y = 0

Step-by-step explanation:

It is always a good idea to look at the question and make some observations about it. Here, you might observe ...

  • all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
  • y is a factor of every exponent

The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.

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To solve the equation, you can write it in terms of powers of 3.

  (3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)

  3^(-5y) = 3^(-15y)·3^(-4y)

  3^(-5y) = 3^(-19y)

  -5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3

  14y = 0 . . . . . . . . . . add 19y

  y = 0 . . . . . . . . . . . one solution

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The rules of exponents we used are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

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4 0
3 years ago
This question is Twelfth grade math please help fast .<br><br> 2x - (2y + 5) = 8
DENIUS [597]

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8 0
2 years ago
What is the solution of the equation 6x - 4 = 2(3x - 2). Explain your steps.​
Vikki [24]

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Pull out like factors :

  8 - 6x  =   -2 • (3x - 4)  

Solve  :    3x-4 = 0  

Add  4  to both sides of the equation :  

                     3x = 4

Divide both sides of the equation by 3:

                    <em><u>x = 4/3 = 1.333</u></em>

7 0
3 years ago
Read 2 more answers
Which of the following is NOT a function help pls!
xxMikexx [17]

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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