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Alenkasestr [34]
3 years ago
13

The percentage of water in an unknown hydrate was determined by heating the sample and driving the water off the sample. Two ind

ependent measurements gave values of 19.564% and 21.731%. Its percentage should be reported as:
Mathematics
1 answer:
Bas_tet [7]3 years ago
8 0

Answer:

It should be reported as 20.648%

Step-by-step explanation:

Since we have 2 different observed values hence we shall use an average of the 2 values to report the result

Thus value is \frac{19.564+21.731}{2}=20.6475%

As we can see that the least count of our observations is upto 3 decimal places hence we have to report a result upto only 3 decimal places thus we need to round off the fourth decimal place thus the digit shall be increased by 1 since we have to drop off 5 and the digit before 5 is 7 which is an odd number.

Thus the result shall be 20.648%

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