Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
Answer:
Step-by-step explanation:
36/78 = 0.46153,,,, nope.. not a choice
36/123 = 0.2926.... so the last answer looks good
Answer:
"101" seems to the appropriate response. The further explanation is provided below.
Step-by-step explanation:
The given expression is:
⇒ 
On solving the brackets, we get
⇒ 
On applying addition, we get
⇒ 
On applying subtraction, we get
⇒ 
