As this procedure is carried out in the natural habitats of this species, this is an <em>in-situ conservation</em>.
<em>In-situ conservation </em>is the type of conservation that occurs on site, where the natural populations of plants or animals are found.
Answer:
The correct answer is B. Worms move through changes in body structure caused by contraction of muscles compressing their watery fluid.
Explanation:
The hydroskeleton consists of a fluid-filled cavity, surrounded by muscles. The fluid pressure and the action of the muscles that border it, serve to change the body's shape and produce a movement such as digging or swimming. The successive contraction of various metamers, which are provided with bundles of circular and longitudinal muscle fibers, stretching and thickening parts of the body, allow it to move horizontally. Hydrostatic skeletons have a role in the locomotion of annelids, nematodes and other invertebrates. The hydroskeleton has similarities with the hydrostatic muscles.
A person whose body weight is more that 20 percent above the recommended level is categorized as obese.
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Answer:
Ribosomes,cytoplasm ,cell wall and circular DNA could be used to justify that the cell is a prokaryote.
Explanation:
Ribosome Ribosome is present in both prokaryotic cell and eukaryotic cell.The prokaryotic cell 70S ribosome which contain 2 subunits the larger subunit is 50S and the smaller subunit is 30s
Cell wall Prokaryotes such as bacterial cell contain cell wall.Cell wall of bacteria contain various carbohydrates which are crosslinked with peptides resulting in the formation of peptidoglycan.
Cytoplasm The cytoplasm of prokaryotic cell such as bacteria contain ribosomes,chromosome and extracellular genetic material called plasmid.
Circular DNA Almost all prokayotic chromosome contain circular DNA molecule that does not contain any free ends.
Answer:
A= 20%
G= 30%
T= 20%
C= 30%
Explanation:
Recall that the sum of all nitrogenous bases in the DNA nucleotide is equal to 100%. And specific base pairings of Adenine to Thymine (A=T), and Cytosine to Guanine (C=G) must be equal.
So, the percentage of Adenine equal thymine, and that of cytosine equals guanine.
Now, A + T + C + G = 100%
So, if Adenine makes up 20% of the DNA nucleotides, Thymine is also 20%.
Then, 20% + 20% + C + G = 100%
40% + C + G = 100%
C + G = 100% - 40% = 60%
So, divide 60% by 2 to obtain the individual percentage of cytosine and guanine. Each will take 30%
Finally, A= 20%; G= 30%; T= 20%; C= 30%
