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atroni [7]
3 years ago
12

How many different values can an algebraic expression like 5+(x+2)

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

wb. lnehiu gliaghjnkmnafvgsbhdnjfnmydabgshdnjmfkg

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A circle has a diameter with endpoints at 3 – 5i and –8 + 2i. What is the center of the circle?
bagirrra123 [75]
So we got the real axis and the imaginary axis
we just need to find the average of the 2 points

remember
midpoint of (x1,y1) and (x2,y2) is

((x1+x2)/2,(y1+y2)/2)
so

average of 3 and -8 is -5/2
average of -5i and 2i is -3/2i

center is -5/2-3/2i
3 0
3 years ago
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Although, in general, you cannot know the sampling distribution of the sample mean exactly, by what distribution can you often a
Vitek1552 [10]

Answer:

b: Normal Distribution

Step-by-step explanation:

4 0
3 years ago
Lines m and n are parallel. What is the measure of angle 5 <br><br> Pls help
Nonamiya [84]

Answer:

48

Step-by-step explanation:


5 0
3 years ago
Ex 2.8<br> 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1
harkovskaia [24]
y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\&#10;y''(0)=20\cdot0^3=0

The value of the second derivative for x=0 is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of 5x^4 is always positive for x\in\mathbb{R}\setminus \{0\}. That means at x=0 there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval [-2,1].
The function y is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

y_{max}=y(1)=1^5-3=-2
4 0
3 years ago
Help !! Picture ^^^^
nikitadnepr [17]
The answer is 78

If you multiply 17x6 you get 102
102 equals the whole rectangle after that you need to get rid of the part that’s not there
so you multiply 8x3 which equals 24
you then subtract 24 from 102 and get 78
6 0
3 years ago
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