Answer:
$15600
Step-by-step explanation:
Minimum number of samples can be calculated using the formula:
N≥
where
- N is the sample size
- z is the corresponding z-score for 95% confidence level (1.96)
- s is the standard deviation of the calorie consumption (450 cal.)
- ME is the margin of error that the researcher is willing to accept. (50 cal)
N≥
=311.2
Therefore, minimum required sample size for 50 cal standard error in 95% confidence is 312
Since the survey costs $50 for each person then the survey costs minimum
50*312=$15600
The question is asking to state if those following scale factors are consider as contraction or expansion, base on my research and further analysis, the possible answer are the following:
3/2 expansion
1/3 contraction
4 contraction
2/5 contraction
4/3 expansion
1/4 contraction
I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarifications
There are mnemonic acronyms out there for reminding you how to do this. I think of it simply as using the distributive property.
(4x-3)(x+5) = 4x(x+5) -3(x+5)
then again
= (4x² +20x) + (-3x -15)
= 4x² + (20-3)x -15 . . . . . . . combine like terms
= 4x² +17x -15
we need to find d=equation, so:
−8+6=−10+10
-8d=-10k+10-6
-8d=-10k+4
d=(-10k+4)/(-8)
So the answer is:
d=(5/4)k-1/2
or
d=1.25k-0.5
He is incorrect He wrote 50, when it should be 5.
