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3 years ago

Which of the following is not an integer? Group of answer choices -1 -2.5 4 25Which of the following is not an integer?

Mathematics

2 answers:

Bas_tet [7]3 years ago

8 0

-2.5. This is because an integer has to be a whole number

Paha777 [63]3 years ago

6 0

The correct answer is -2.5

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Anyone know this Geometry problem?

Yuliya22 [10]

Answer:

ST = 20

Step-by-step explanation:

RT is the sum of RS and ST

Replacing with length you get:

17 + x + 6 = 3x - 56

17 + 6 + 5 = 3x - x

28 = 2x

14 = x

ST = x + 6 = 14 + 6 = 20

6 0

3 years ago

0.68 = 0.6 + ___ = ____ x 0.1 + 8 x ____

8_murik_8 [283]

0.68 = 0.6 + .08 = 6 x 0.1 + 8 x .01

They should all equal 0.68 :)

5 0

3 years ago

What is the constant rate of change from the graph? <br> 2 <br> 10 <br> 5 <br> 1/5

Dvinal [7]

I believe the answer is 0.5

3 0

3 years ago

there are 27 red or blue marbles in the bag the number of red marbles is five less than three times the number of the blue marbl

alexdok [17]

So assuming that the total =27
r+b=27
r=-5+3b
r=3b-5
subsitute 3b-5 for r in first equation
3b-5+b=27
4b-5=27
add 5
4b=32
divide by 4
b=8
subsitute
b+r=27
8+r=27
subtracct 8
r=19

red=19
blue=8

4 0

3 years ago

A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro

pshichka [43]

Answer:

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed $\frac{dx}{dt}$ = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=(x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=rx$

$\frac{dh}{dt}=\frac{rx}{h}$

When automobile is 30 miles past the intersection,

For x = 30

$\frac{dh}{dt}=\frac{30r}{h}$

Since $h=\sqrt{d^{2}+(30)^{2}}$

Therefore,

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}$

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

3 0

3 years ago