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laiz [17]
3 years ago
7

What are the first five numbers of pie

Mathematics
1 answer:
kolezko [41]3 years ago
6 0
3.14159



hope this help
brainless plz
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How to write 5/9 + 5/9 as a mixed number ​
velikii [3]

Answer:

You add the numerators so 5 + 5 is 10. So its 10/9. We only added the numerators because the denominators were the same. So then 10/9 simplified by minusing 9 from ten because ten is the denominator the answer is:

 1 1/9

Step-by-step explanation:

3 0
2 years ago
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Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0<×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
In how many ways can 3 Americans, 4 Frenchmen, 4 Danes and 2 Italians be seated in a row so that those of the same nationality s
kaheart [24]
Answer (13 of the original arrangements are duplicates now, as AAAF F F FDDDDCC, AAF F F FDDDDCCA, ..., CAAAF F F FDDDDC are identical): 900900/13 = 69300.
4 0
3 years ago
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The systolic blood pressure of adults in the USA is nearly normally distributed with a mean of 122 and standard deviation of 22
marin [14]

Answer: 4.27% of adults in the USA have stage 2 high blood pressure.

Step-by-step explanation:

Let x be a random variable that denotes a person with high blood pressure .

Given: Average blood pressure: \mu=122

Standard deviation: \sigma=22

Someone qualifies as having Stage 2 high blood pressure if their systolic blood pressure is 160 or higher.

The probability that an adult in the USA have stage 2 high blood pressure:

P(x\geq160)=P(\dfrac{x-\mu}{\sigma}}\geq\dfrac{160-122}{22})\\\\=P(z\geq1.72)\ \ \ [z=\dfrac{x-\mu}{\sigma}]\\\\=1-P(z

Hence, 4.27% of adults in the USA have stage 2 high blood pressure.

6 0
2 years ago
The dance committee hired a DJ for the fall dance. The DJ charges $125 per hour plus $55 for an assistant. The committee wants t
lorasvet [3.4K]
He can play for 4 hours
3 0
3 years ago
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